ok, I think I'm getting this, here are some quick questions. how would I pass the array in the prototype before main, if it hasn't been declared yet, and I would like to understand how why I only put a dimension in the second [] of my 2 dimension array while leaving the forst one empty. just some simple answers are needed, please don't think I am extremely stuped.
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Size information about the array is not passed along with the array. You can have the dimension on the end, presumably because it then has the appearance of passing an array of pointers (the compiler never sees them as arrays), but the following are all just as good since the compiler only sees the pointers, anyways:
Code:void f(char[][16]); void f(char[][]); void f(char**);
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I think I can get it from here, Thanks to everyone who helped, despite the low levelness of the questions.
This has been a public service announcement from GOD.
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>> how would I pass the array in the prototype before main
The prototype doesn't need the actual data, it just need to know what to do when the data enters.
>> why I only put a dimension in the second [] of my 2 dimension array while leaving the forst one empty
You can put both, if you care to:
Code:void manipulate(char array[10][10]) { array[0][0] = 0; } int main() { char x[10][10]; manipulate(x); return 0; }
Code:#include <cmath> #include <complex> bool euler_flip(bool value) { return std::pow ( std::complex<float>(std::exp(1.0)), std::complex<float>(0, 1) * std::complex<float>(std::atan(1.0) *(1 << (value + 2))) ).real() < 0; }
