I made a function that has a void pointer as a parameter. I don't think I did it right (I've never made a function with a void pointer before). It always returns 0, no matter what. Here is my code:
PS: There are more cases in the actual function, I just copied and pasted one.Code:unsigned int BTFImage::GetData(unsigned char SetFlag, void* dest) { switch (SetFlag) { case BTF_WIDTH: dest = &width; return height; default: return 0; } }
> dest = &width;
Doesn't work for the same reason SetFlag = 1 wouldn't change the value in the caller.
Either pass a void** parameter and do
*dest = &width;
Or pass a void* parameter as a reference (since this is C++)
I hope width isn't a private class member, that would be very bad C++
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
You could also do:
This, however, places the burden on the caller to allocate space for the data.Code:case BTF_WIDTH: *(int *)dest = width; return height; default: return 0;
You ever try a pink golf ball, Wally? Why, the wind shear on a pink ball alone can take the head clean off a 90 pound midget at 300 yards.
