Thread: An algorithm about C/C++

  1. #16
    & the hat of GPL slaying Thantos's Avatar
    Join Date
    Sep 2001
    1) How can i prevent user to enter a incorrect number.
    Put your code to the user input into a post checking loop (do while) and keep yelling at the user until they entire something that is valid.

    I think i must declare four functions: transToBinary, transToDecimal, transToHexa, transToOcta
    You can do it with one function, just pass the base to the function.

    Is there anyone there who can solve this problem and help me to make this program
    We are not in the buisness of writting homework here.

    Other things I've noticed:
    use tolower() or toupper() instead of the stacked case statements. While its legal its also fugly for this usage.
    You need to get the number from the user as a string and not an int. You then have to convert the string into an int depending on the base.

  2. #17

    Um, in my experience, one need not know how many numbers there are in the number...

    I know this is true of base 10, but i'm not sure about the others every time.

    You look at each number in turn:

    0 -> current number
    10 -> base
    Mark A
    convert to decimal ( '1' ) -> new digit
    ( current number * base ) + new digit -> current number
    Goto mark A and repeat for each character

    GCC on Red Hat 8.1 (Primary)
    GCC on Mac OS X 10.2.4 (Secondary)

    MinGW on XP

  3. #18
    Registered User
    Join Date
    Oct 2003
    Try this:

    #include <iostream.h>
    #include <string.h>
    #include <ctype.h>
    int main() {
    int number, base, i, j;
    char b, input[50];
    char num[]="0123456789abcdef";
    do {
    	cout<<"\nBase? [d]ecimal, [b]inary, [o]ctal, [h]ex:";
    	switch(b) {
    	case 'd': base=10; break;
    	case 'b': base=2; break;
    	case 'o': base=8; break;
    	case 'h': base=16; break;
    	default: base=0;
    	if(base==0) cout<<"\nplease input only d, b, o, or h.\n";
    } while(base==0);
    cout<<"\ninput ";
    switch(base) {
    case 2: cout<<"binary"; break;
    case 8: cout<<"octal"; break;
    case 10: cout<<"decimal"; break;
    case 16: cout<<"hexadecimal"; break;
    cout<<" number: ";
    for(i=0; i<strlen(input); i++)
      for(j=0; j<base; j++) {
    	  if(num[j]==tolower(input[i])) {
    return 0;

  4. #19
    End Of Line Hammer's Avatar
    Join Date
    Apr 2002
    moving to the c++ forum...
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

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