Thread: I don't know what this c++ method means!

void Print(ostream&) const – this constant member function will display data of the objects through the ostream object in the argument.

This is something I have to program.
I guess I am suppose to take in an ostream object such as
"cout"

but i have no clue what to write
Please help

nobody knows?

I think i figured it out

I can take an object like

obj.Print(cout).

now my method can be


cout<<(this.value);



I think that's all there is to it?!?

This is kind of like overloading the >> ostream operator.

Code:

void ClassName::Print(&ostream os){
    os >> classvariable;
    os >> anotherprivatevariable;
}
.
.
Print should be public.
.
.
ClassName.Print(cout);

I think this is what you would do.

curlious
why did you use the >>operator?

I read the api for cout and thought i had to use

<<(const & primitive_type);

??

opps my bad you are correct it is the << operator but using
cout << this.value will not work if value is private.
classname.Print(cout); will work if you define the function like I said.

Code:

you can overload the << operator like this

ostream & operator<<(ostream & os, const ClassName & object){
   os<< classvar;
   return os;
}

you should make the prototype a friend function in your class declaration

then you can do this in main
cout << classobject;