Yes!
No.
Hi, just felt curious about this one thing (sorta spur of the moment pointless idea). Can you overload the operators for basic data types like int? And if so, if you made a typedef of an int for example and called it "mytype", could you overload an operator for int and also overload the same operator for mytype, differently?
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Nope not possible. If overloading basic or primitive datatypes would be possible every programmer could introduce a new basic datatype. Problem: Ambiguous.Can you overload the operators for basic data types like int?
01000111011011110110111101100100 011101000110100001101001011011100110011101110011 01100100011011110110111001110100 01100011011011110110110101100101 01100101011000010111100101110011 0110100101101110 01101100011010010110011001100101
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Oh right
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No, and no.
Operators involving only primitive types are set in stone, and cannot be changed.
Also, a typedef is not a new type, it's only "shorthand". The true type will always be substituted during compilation.
Yeah, that was what I thought, but it was a sort of sudden "what if" idea that I felt might be worth exploring since I wasn't 100% sure
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Just FYI, enums are technically not the same as ints (even though they're the same internally), so you can overload an enum differently from an int.
Hmm, so I can have 2 different int "types", with one of them overloadable?...
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You could make an Integer class or something... why would you WANT to overload the operators of an int, actually?
Well, no real reason... out of idle curiosity I guess
#ifdef SOME_CONDITION
should work
#else
usually don't
#endif
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It's all about the types. C++ is very strongly typed. It's designed so that you can use the type system to help you catch errors and debug code. The fact that an enum and an int are fundamentally the same doesn't matter: the type is different.Originally posted by Hunter2
Well, no real reason... out of idle curiosity I guess
#ifdef SOME_CONDITION
should work
#else
usually don't
#endif
Ok, thanks. Lots of useful facts pouring in here
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