Hi, im passing a pointer containing a string to a function im then using
int isNumberString(char *pNumberStringPtr)
{
if(strcmp( *pNumberStringPtr, "ONE" ) != 0 )
{
return 0
}
else if (strcmp( *pNumberStringPtr, "ONE" ) = 0 )
{
return 1;
}
}
this is a cut down version
it come sup with this error
error C2664: 'strcmp' : cannot convert parameter 1 from 'char' to 'const char *'
why is that, i dont understand
any help would be really appreciated
> if(strcmp( *pNumberStringPtr, "ONE" ) != 0 )
Should be
if(strcmp( pNumberStringPtr, "ONE" ) != 0 )
pNumberStringPtr is already a char* (which is what strcmp expects). By putting a * in there, you dereference the pointer to the char it points at (*pNumberStringPtr is a char).
Hence the error message
cannot convert parameter 1 from 'char'
> what *pNumberStringPtr is
to 'const char *'
> what strcmp expects (and what pNumberStringPtr is)
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
ah so you mean change *pNumberStringPtr back to just pNumberString
thanks alot ill give it a try, you helped me out again
if i change it back to pNumberString it tells me unknown identifier pNumberString as it is ohnly declared locally in the main function and not the one where i have sent it too, if you know what i mean
sorry i miss read your answer ill try again
You should also change:
else if (strcmp( pNumberStringPtr, "ONE" ) = 0 )
to
else if (strcmp( pNumberStringPtr, "ONE" ) ==0 )
