Thread: ASCII to Binary and Hex

Dude to get ASCII code do this:

Code:

#include <iostream>
using namespace std;

int main()
{
char letter;
cout<<"Char: ";
cin>>letter;
cout<<"ASCII: "<<(int)letter;
return 0;
}

But this topic relates back to what I was coding for you. I can't seem to get it to work.

It seems right but it doesn't do the job I expect it to... Can anybody see the mistake?

Code:

#include <iostream>
using namespace std;
char bin(int x)
{
    char binn[31];
    for(int y=0;y<32;y++)
    {
        if(x>=(2^(32-y)))
        {
            binn[y] = '1';
            x = x - (2^(32-y));
        }else{
            binn[y] = '0';
        }
    }
    return *binn;
}

int main()
{
    int number;
    cout<<"ASCII Value: ";
    cin>>number;
    cout<<bin(number);
    return 0;
}

So you are trying to output a binary value?

Code:

int val = 255;
const unsigned int mask[] = {0x80, 0x40, 0x20, 0x10, 0x08, 
0x04, 0x02, 0x01};
const unsigned int mask2[] = { 10000000,1000000,100000,10000,1000,100,10,1};
int result = 0;

int binconvert(int num)
 {
     int x=0;
 for (int i=0;i<8;i++)
 {
  if (num&mask[i])
        x+=mask2[i];   }
  return x;
 }

Rather than this:

Code:

cout << "ASCII: " << (int)letter << endl;

You should be using the C++ typecasts, the one you need in this case is:

Code:

cout << "ASCII:" << static_cast<int>(letter) << endl;

Correct me if I'm wrong.

cout<<"Ox"<<(int *)letter; //will output hex such as 0x000000FF
cout<<int(letter); //will output decimal

or,

Code:

#include <iostream>
#include <iomanip>
using namespace std;

int main()
{
	char letter;

	cout<<"char: ";
	cin>>letter;
	cout<< setbase(16) << int(letter); //for hex
        cout<< setbase(8) << int(letter);//for octal
        cout<< setbase(10) << int(letter);//for decimal the set base 
                                          //isn't really needed on for   decimal                                                       
}

or,

Code:

#include <iostream>
using namespace std;

int main()
{
	char letter;
	cout<<"char: ";
	cin>>letter;
	cout<< hex << int(letter); //hex
        cout<< oct << int(letter);   //oct
        cout<< dec << int(letter);  //dec, you don't really need to
                                   //specify dec here either.
}

sorry to be redundant, just wanted to show a few ways to do it

I'm aware of a few errors, as this was a quicky, but that doesn't tell me if those two syntaxes are the same thing or if there is a slight difference between them.

I still haven't got this to work. I'm not aiming to cout the binary numbers, I'm aiming to have it stored in a variable. I have tried many codes so far, all from this topic as well, and I can't get what I want. Here I have another error, can anyone see it ? The program is always giving me "1" instead of a whole 8bit binary code.

Code:

#include <iostream.h>
#include <conio.c>



int tobin(char string)
{
    int binnumber[8];
    for(int i = 0; i < 8; i++)
    {
        if(((int)string) >=(2^(7-i)))
        {
                binnumber[i] = 1;
                ((int)string) = ((int)string) - (2^(7-1));
        }
        else
        {
                binnumber[i] = 0;
        }
    }
   return * binnumber;
}




int main()
{
    char number;
    cout << "Text : ";
    cin >> number;
    cout << tobin(number);
    cout << endl;
    system("pause");
    return 0;
}