Thread: Array of files

a file which encapsulates lets say 3 files

MyFile([file1][file2][file3])

First you say an array of files, then you say a file encapsulating many files. What EXACTLY do you want?

Do you mean something like this?

Code:

FARRAY fArray[5]; //short for filearray

LoadFileIntoArray(&fArray,0,"filename.ext");
LoadFileIntoArray(&fArray,1,"filename2.ext");
//etc...
//then later...

int dispFile(const FARRAY fArray,int nIndex)
{
cout << (char *)(fArray[nIndex].data);
return 0;
}

That sort of thing would allow you to load every byte from a file into a large BYTE array, (hopefully) allocated somewhere other than the local stack, then access that data as you please.

Without any compression, I could think of an easy way to do this. Create a structure for a file that will include a header, and x number of data blocks. The header should include the details of each file contained in the overall file, including the offset, length, filename, etcetera. You can then use whatever file ouputing technique you want. Eg: (file contents)

Code:

[HEADER]
["blah.dll",120,2500]
["readme.txt",2621,360]
[/HEADER]
blah.dll contents output right here, at offset 120
readme.txt contents output here, at offset 2621

Something like that should suffice.