How can I get random numbers without repeated?? What I don't know is how can I check the repeated numbers. Any examples of checking repeated numbers?? thx!!
How can I get random numbers without repeated?? What I don't know is how can I check the repeated numbers. Any examples of checking repeated numbers?? thx!!
> How can I get random numbers without repeated?
Store the ones you've generated in an array.
When you generate a new random number, scan the array to see if you've seen it before
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
I did what u do... However, it doesn't work..... Can u help me to correct it?? What I wrote:
Thanks!!Code:#include <iostream.h> #include <stdlib.h> #include <time.h> inline void randomize(){ srand((unsigned)time(NULL)); } int main(void){ int num1,num2[5],j=0; randomize(); for (int i=0; i<5; ++i){ while(j < 5){ num1 = (rand() % (1000-100)) + 100; while((num1 == num2[0])||(num1 == num2[1])||(num1 == num2[2])||(num1 == num2[3])||(num1 == num2[4])||(num1 == num2[5])){ num1 = (rand() % (1000-100)) + 100; } cout << num1 <<" "; num2[j] = num1; j++; } cout <<endl; } return 0; }
I can't work it out!! What's wrong with my codes?? a help would be appreciated! Thanks!!
Code:#include <iostream.h> #include <stdlib.h> #include <time.h> inline void randomize(){ srand((unsigned)time(NULL)); } int main(void){ int num1[9],num2 = 1; randomize(); for(int i=0;i<10; i++){ num1[0] = (rand() % (1000-100)) + 100; do{ for(int i=0;i<num2;i++){ if (num1[num2]==num1[i]) break;; if (i==num2) num2++; } }while (num2<9); } for(int j=0;j<9;j++){ cout << num1[j]; } cout<<endl; return 0; }
The codes above are for random! I think the checking unrepeated numbers part is wrong!!
I change again, but still can't work!! Please help me!! Thanks!!
Code:#include <iostream.h> #include <stdlib.h> #include <time.h> inline void randomize(){ srand((unsigned)time(NULL)); } int check(int num1,int i); int main(void){ int num1 = 0; randomize(); for (int i=0; i<5; ++i){ num1 = rand() % 7; check(num1,i); cout << num1 <<" "; } cout <<endl; return 0; } int check(int num1,int i){ int num2[5]; for (int j=0; j<i; j++){ while (num1 == num2[j]){ num1 = rand() % 7; check(num1,i); } num2[j] = num1; } return (num1,i); }
> inline void randomize(){Code:#include <stdio.h> #include <stdlib.h> #include <time.h> #define MAX_UNIQUE 10 // is the new random number in the 'num' previous old random numbers int seen_before ( int old_rands[], int num, int new_rand ) { int i, seen = 0; for ( i = 0 ; i < num && !seen ; i++ ) { seen = old_rands[i] == new_rand; } return seen; } int main ( ) { int seen[MAX_UNIQUE]; int i, r; srand(time(NULL)); for ( i = 0 ; i < MAX_UNIQUE ; i++ ) { do { r = rand() % 100; } while ( seen_before( seen, i, r ) ); seen[i] = r; printf( "%d ", r ); } return 0; }
Why?
What is the point of inlining a one line function, which is only called once?
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
alternate version in pseudocode
main()
int num1;
//array to store random numbers, initialized to -1
int numbers[5] = {-1};
int i;
//to keep track of how many unique random numbers found
int index = 0;
//flag indicating random number is unique in array.
char found;
//seed random number generator using srand() or randomize
srand()
//want to find 5 unique rand numbers
while index < 5
//set flag each time through loop
found = 'n';
//generate random number
num1 = rand % 100;
//check this random number against numbers in array
for(i; i < 5; i++)
{
//if ranom number already in array
if numbers[i] == num1;
//change flag
found = 'y'
}
//if flag not changed then this random number is unique
if found == 'n'
{
//so add it to the array at the current index
number[index] = num1;
//and increment the index for next number
index++;
}
end while
