Thread: Programming not running

  1. #1
    Registered User
    Join Date
    May 2003
    Posts
    12

    Programming not running

    I have gotten my program to compile but it is not running properly. What is wrong? Also how do I incorporate an exit routine.


    <code>
    #include <iostream>

    using namespace std;


    int get_date(int, int, int); // function declaration
    int calc_year(int the_year);


    int main()
    {

    int m, day, year, our_day; //month, day and year

    cout<< "\nEnter any date as three sets of numbers.\n";
    cout<< "(month, day, year). Example: 7 29 1971\n";
    cout<<"Entering invalid dates will exit the program.\n";
    cout<<"Enter date: ";
    cin>>m>>day>>year; //input date

    // The conditional inside the while statement could get you into a
    // lot of trouble. You need to check your logic as to how you want it
    // to really work.


    while((m != 13)&(day !=32)&(year != 0000)) //Invalid dates exit the loop
    {
    our_day = get_date(m, day, year);
    //Passes the three values to get_date function


    //Turns a numerical month into a named month when printed

    switch(m)
    {
    case 1:
    cout <<"January "<< endl;
    break;
    case 2:
    cout <<"February "<< endl;
    break;
    case 3:
    cout <<"March "<<endl;
    break;
    case 4:
    cout <<"April "<<endl;
    break;
    case 5:
    cout <<"May "<<endl;
    break;
    case 6:
    cout <<"June "<<endl;
    break;
    case 7:
    cout <<"July "<<endl;
    break;
    case 8:
    cout <<"August "<<endl;
    break;
    case 9:
    cout <<"September "<<endl;
    break;
    case 10:
    cout <<"October "<<endl;
    break;
    case 11:
    cout <<"November "<<endl;
    break;
    case 12:
    cout <<"December "<<endl;
    break;
    }


    //Switch statement for the days of the week
    switch (day)
    {
    case 1:
    cout <<"Tuesday\n"<<endl;
    break;
    case 2:
    cout <<"Wednesday\n"<<endl;
    break;
    case 3:
    cout <<"Thursday\n"<<endl;
    break;
    case 4:
    cout <<"Friday\n"<<endl;
    break;
    case 5:
    cout <<"Saturday\n"<<endl;
    break;
    case 6:
    cout <<"Sunday\n"<<endl;
    break;
    }

    cout<<"\n\nEnter date: ";
    cin>>m>>day>>year;

    }


    return 0;

    }

    get_date(int m, int day, int year); //function call


    //get_date function
    int get_date(int the_m, int the_day, int the_year)
    {

    //values for months of the year
    int jan = 1, febr = 4, mar = 4, apr = 0,
    may = 2, june = 5, july = 0, aug = 3,
    sept = 6, octo = 1, nov = 4, dec = 6;

    int the_month, the_date; //Variables used in calculations

    if(the_m <3)
    {
    if(the_m == 2)
    {
    the_date = febr + the_day;
    }
    else{
    if(the_m == 1)
    {
    the_date = jan + the_day;
    }
    }
    }
    else
    {

    switch(the_m)
    {
    case 3: the_month = mar; break;
    case 4: the_month = apr; break;
    case 5: the_month = may; break;
    case 6: the_month = june; break;
    case 7: the_month = july; break;
    case 8: the_month = aug; break;
    case 9: the_month = sept; break;
    case 10: the_month = octo; break;
    case 11: the_month = nov; break;
    case 12: the_month = dec; break;
    }


    if((the_year%4 == 0) &! (the_year%100 == 0))
    {
    the_date = the_day + (the_month + 1);
    }
    else{
    if(the_year%400 == 0 )
    {
    the_date = the_day + (the_month + 1);
    }
    else
    {
    the_date = the_day + the_month;
    }
    }
    }
    int first_day; //declares int

    first_day = calc_year(the_year); //passing the_year to the new function, and assigning the return value to first_day

    int this_day; //declaration for calculation.

    this_day = the_date + first_day; //add the return value(count_day) to the_date and assign the sum to this_day.

    //While () loop counts backwards by decrementing until it reaches the day

    while(this_day %= 7)
    {
    this_day %= 7;
    }

    this_day = this_day - 1; //Make the day before Monday (0 - 1) be Sunday
    if(this_day == -1)
    {
    this_day = 6;
    }

    return this_day;

    return 0;
    }


    //calc_year function

    int calc_year(int the_year)

    {

    int count_day = 0; //start on Monday

    //1900 started on a Monday, so don't enter the loop

    for(int i = 1901; i <= the_year; i++)
    {
    count_day++; //day of the week.
    if(count_day >= 7)
    {
    count_day = count_day - 7;
    }

    //reset at the end of each week

    if((0 == ((i-1)%4)) &! (0 == ((i-1)%100)))
    {
    count_day = count_day + 1; //adjust for leapyear
    }
    else
    {
    if(0 == ((i-1)%400))
    {
    count_day = count_day + 1;
    }
    }



    }

    if(count_day == 7) //Make the day after Sunday (6 + 1) become Monday
    {
    count_day = 0;

    }

    return count_day;
    }


    </code>

  2. #2
    ATH0 quzah's Avatar
    Join Date
    Oct 2001
    Posts
    14,826
    See the column to the left for the proper code tag format.

    That aside:
    Code:
    while((m != 13)&(day !=32)&(year != 0000))
    You are using the bitwise and. You want want the logical and. That is to say:
    Code:
    while( foo && bar )
    You've got another problem:
    Code:
        while((m != 13)&(day !=32)&(year != 0000)) //Invalid dates exit the loop
        {
            our_day = get_date(m, day, year);
        
            switch(m)
            {
                 ...
            }
    
            switch (day)
            {
                ...
            }
    
             cout<<"\n\nEnter date: ";
            cin>>m>>day>>year;
        }
        return 0;
    }
    
    get_date(int m, int day, int year); //function call
    
    Why do you have a function call outside of your main loop? This is actuallly a function prototype, not an actual call to the function. You usually prototype functions before the main loop.

    Quzah.
    Last edited by quzah; 06-27-2003 at 09:12 PM.
    Hope is the first step on the road to disappointment.

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