I tried to solve the program for a look and read digit. The user input a number like 488667 and the result of the program should be 14282617 with no function,array, or pointer used. To solve the program I get an error which is that the counter does not cumulate.Please if somebody have any suggestions I would appreciate it.

Code:
```#include <iostream>
#include <math.h>
using namespace std;

int main()
{

int m,c,i,n;
int counter=0;
cout<<endl<<endl;

cin>>n;

int s =log10(n);

for(i=s;i>=0;i--)

{

c=pow(10,i);
m=(pow(10,(s-i)));

if(((n/(c))%10)==((n/(c/10))%10))
{
counter+=1;

}

cout<<counter<<(n/c)%10;

if(((n/(c))%10)!=((n/(c/10))%10))

cout<<"1"<<(n/c)%10;

}

return 0;

}```
Thanks.

2. I recommend long data type instead of int. As for the algorithm, you designed it, so debug it.

Kuphryn

3. One thing... I'd advise using <cmath> instead of <math.h>. The former is a member of the standard library, and encapsulates its members in the std namespace. Aside from that, what is your algorithm supposed to be doing?

Zach; the algorithm is that if the first number is the same as the number after it( repeated number) I should see how many times it reapeats it self and then print the number of times and the number itself if not just print out number 1 and the number itself.
for example when I input the number 7488999 the secreen should show 17142839 i.e look and read . As for "kuphryn"
please if you do not want to help just do not, I know it is my code but if I'm able to debug it I would not post it and I think this forum is to offer help and information exchange it.Thanks

5. I got bored, so I tried my hand at this quick. Unless you plan on doing some actual math with these numbers, its easier to handle it as a string.
Code:
```#include <iostream>
#include <string>
using std::cout;
using std::cin;
using std::string;
using std::endl;

int main()
{
string input;

cout << "Please input a number: ";
cin >> input;

int size=input.size();
int count=1;
for(int x=0;x<size-1;++x)
{
if(input[x]==input[x+1])
count++;
else
{
cout << count << input[x];
count=1;
}
}
cout << count << input[size-1];
}```
It should work fine I believe.

6. but if you are looking to do math with it...

use the modulus '%'

and with a few for loops and such you should have your answer.

7. Thanks guys, yeh.. I should do the math no string allowed yet. I did used the Mod but my problem was with counter and I found out the reason why it is not accumulating because it was not reading the next digit right. Thank you very much any way for the help...I appreciate it.