Thread: String Literals

Is there a way to make a program treat a variable like a string literal?

i.e:

Code:

void func(any & x)
{
      char * temp;
      // get data
      x = temp;
}

And not losing the data because it goes out of scope, sort of like this?

Code:

void func(any & x)
{
      x = "temp";
}

(without dynamically allocating)

Try 'const char * temp;'. I believe that's how literals are treated in C++ normally.

Can someone else elaborate on this, please?

I think I tried that, but I'm not sure... I'll try that now.

I tried, alas, nope.

Thanks anyway

static is nice...

only its useless for this.

this will be run multiple times, and the data inside the class can't be changed when the data is changed

So declare the data mutable and make your function a 'const' function.

its an ostream overload, so its not inclass

Originally posted by Trauts
its an ostream overload, so its not inclass

It doesn't matter, it accepts a class as one of its arguments, no? Declare whatever data inside that class which will be changed as 'mutable'. eg. mutable int m_data;
I really don't think you're explaining yourself very well... some real code would be of use right about now.

http://cboard.cprogramming.com/showt...threadid=39570

the real problem on that post is the fact that it can't choose which operator when the bitshift ones are there... it tries to take the ostream in the template.

I don't know how to fix that.