Thread: Passing pointer of class type

ok i was thinking about making some (simple) code to see whether two rectangles (not actual ones--only the numbers like coords and dimensions exist) are overlapping

i created a "Rect" class and then i got down to passing in the values in each rectangle.

what im wondering is if it is possible to do it without passing in the height,width, and coordinates directly:

Code:

if (isOverlapping(&Rect1,&Rect2))

instead of something like this:

Code:

if (isOverlapping(Rect1.getHeight(),Rect1.getWidth(),Rect1.getXCoord(),Rect1.getYCoord());

i tried the first method and in the function:

Code:

 if (((*r1.getRectYCoord+*r1.getRectHeight)>=(*r2.getRectYCoord))&&((*r1.getRectYCoord+*r1.Height)<=(*r2.getRectYCoord+*r2.getRectHeight)))
    return true;
//trying to use a pointer the the class type

and I get a compiler time error:

36 main.cpp
request for member `getRectYCoord' in `r1', which is of non-aggregate type `Rect *'
...

im kinda tired right now so i might be doing something entirely stupid...but i dont think so...*yawns*

Yeah, that's just what I needed (encouragement included)...I'm going to sleep and I'll remember it tomorrow morning when I think how boring school is going to be...

"what im wondering is if it is possible to do it without passing in the height,width, and coordinates directly"

Yes, and that's the way you should do it.

bool isOverlapping(const Rect& r2) const

If you are going to include the function in your class, you only need to pass in one parameter because the members of the object for which you are calling the function on can be referenced directly in the body of the function e.g

Rect r1, r2;

if(r1.isOverlapping(r2))
{...}

bool isOverlapping(const Rect& r) const
{
if(y_coord > r.y_coord){...}
}