No the modulus operator produces a remainder, there is no value that you could divide by 99 and add 1 that would produce 100.rand() % 99 + 1 will give you 100. If the random number is 99+1, do the math in your head.
98%99=98+1=99
99%99=0+1=1
197%99=98+1=99
198%99=0+1=1
etc...
but
99%100=99+1=100 //What we want
100%100=0+1=1
zen
Zen is right.
To get the output 100 from rand()%99+1, rand()%99 must be 99. What rand()%99 do is divide the number generated from rand() with 99, and return the remainder from the division.
Example:
5%5=0 (5/5=1, Remainder=0, 1*5=5)
10%5=0 (10/5=2, Remainder=0, 2*5=10)
11%5=1 (11/5=2, Remainder=1, 2*5+1=11)
13%5=3 (13/5=2, Remainder=3, 2*5+3=13)
29%5=4 (29/5=5, Remainder=4, 5*5+4=29)
30%5=5 (Not correct, you can divide (subtract) the remainder once more)
As you can see, the remainder cannot be equal or higher than what you divide with, which makes it impossible for rand()%99 to generate the number 99.
MagosX.com
Give a man a fish and you feed him for a day.
Teach a man to fish and you feed him for a lifetime.
Wow i wanted to know the same question
but how do u change the random numbers so they are smaller than 100 and bigger than 1
thanks for any answer
"Yes, I am a criminal. My crime is that
of curiosity. My crime is that of judging
people by what they say and think, not
what they look like. My crime is that of
outsmarting you, something that you
will never forgive me for."
quote from:
+++The Mentor+++
random number between 35 and 40 inclusive:
srand() or randomize() once as per previous discussion:
x = 35 + (rand() % 6)
I'm not sure what you mean, but I'll make a try:
If you want a random number from 10 to 19, you use this: rand()%10+10.
General syntax: rand()%Range+Start
Range is how many different numbers you want (from Start to (Start+Range-1) ).
Start is the first number (in the above case: 10)
Example:
rand()%5+10 A random number from 10 to 14
rand()%20+80 A random number from 80 to 99
rand()%100+100 A random number from 100 to 199
Perhaps you want a random number from all even numbers between 10 and 19 (10, 12, 14, 16 & 18):
2*(rand()%5)+10
-Hope you didn't get even more confused
MagosX.com
Give a man a fish and you feed him for a day.
Teach a man to fish and you feed him for a lifetime.
PS: I Love to use different colours in the text, as you may have noticed.
MagosX.com
Give a man a fish and you feed him for a day.
Teach a man to fish and you feed him for a lifetime.
Thanks Magos =)
"Yes, I am a criminal. My crime is that
of curiosity. My crime is that of judging
people by what they say and think, not
what they look like. My crime is that of
outsmarting you, something that you
will never forgive me for."
quote from:
+++The Mentor+++
You would use rand()%100 + 1
rand()%100 = 0-99 because it give you the remainder there is no way to get a reamainder of 100 when dividing by 100.
to make it into an actually game-like program......
do the prompts to user..........cin the data.......then use a for loop to count from 10 to 0 (number of try the user gets to guess the number correctly)......
example
guess // is number entered by user
rand_num// is the rand number the program generates
answer// either 'Y' or 'N' meaning yes or no to play game again.
for(int i=0;i<=10;i--)
{
if (guess!=rand_num)
{
cout << "YOu have "<<i<<"tries left.\n";
}
else if (guess==rand_num)
{
cout<< "Good Work............You got the number in ony " << i << " tries.\n";
}
hows that look?
i was thinking of adding....... this at the end
}while(answwer=='y'||'Y')
}
Use srand() and rand()%101.
what is so great about rand()%100+1,
The original post asked about a random number generator between 1-100, and rand()%100+1 will do this.
rand()%101 will produce random numbers between 0-100.
zen
