Thread: setting the width

Code:

#include <iostream>
using namespace std;

void  initialize(double [], int);
void  process   (double [], int);
void  format              (void);
void  display   (double [], int);

int main()
{
	double array[5];

	cout << "Enter five numbers\n" << endl;

	initialize(array, 5);

	process(array, 5);

	format();

	display(array, 5);

	return 0;
}

void  initialize(double array[], int size)
{
	for (register int i = 0; i < size; i++)
	cin >> array[i];
}

void  process   (double array[], int size)
{
	for (register int i = 0; i < size; i++)
		array[i] = array[i] * 2;
}

void  format                        (void)
{
	cout.precision(2);

	cout.width(10);

	cout.setf(ios::fixed | ios:: showpoint);
}

void  display   (double array[], int size)
{
	cout << "\nThe numbers doubled are..." << endl;

	for (register int i = 0; i < size; i++)
		cout << array[i] << endl;
}

Why doesn't cout.width(10) work?

The only way I can get it to work is to change the cout statement in the display function's definition to cout << setw(10) << array[i] << endl;

I don't want to use that way since it defeats the purpose of having a formatting function, and the setw method requires that I add #include <iomanip>

Is there a way to do this without pointers?

Pointers are scary.

I think I saw one stalking me in the streets the other night. *shivers*