a file problem !!

**girlzone** · 04-14-2003

hi

i have a small problem here.
i have written a program ( it is supposed to be easy and simple

) . it computes numeric grades for a course. The course records are in a file that will serve as the input file. The input file is in exactly the following format: each line contains a student's last name, then one space, then the student's first name, then one space, then ten quiz scores all in one line. The quiz scores are whole numbers and are separated by one space. the program will take its input from this file and send its output to a second file. The data in the output file will be exactly the same as the data in the input file except that there will be one additional number(of type double) at the end of each line. This number will be the average of the student's ten quiz scores.
well, every thing worked fine except for the average. so, this is my code and thank you

note:
i only took the basics in C++ i took functions and files (I/O streams)... i didn't take strings,structures, classes, pointers, linked lists, or arrays..

Code:

 
#include<iostream>
#include<fstream>
#include<cstdlib> 
using namespace std;

void check ( ifstream& in_f, ofstream& out_f );
// This function checks if the files are successfully opened...
 
void copy ( ifstream& in_file , ofstream& out_file ) ;
// This function copies the information from the input file to the output file
// as well as computing and writing the average for each student....

int main ()


{
	ifstream in_stream ;
	ofstream out_stream ;

		cout << " Hello *_* welcome to my                  program ... \n" ;
		check ( in_stream , out_stream );
		copy ( in_stream , out_stream );
    	                in_stream.close();
		out_stream.close();
		cout << " That's all for now *_* see you later \n";

		return 0 ;
}


void check (ifstream& in_f, ofstream& out_f )
{
	in_f.open("in_file.dat") ;
		if ( in_f.fail() )
		{ 
          cout << " Input file opening failed ...\n" ;
		  exit (1) ;
		}

		out_f.open("out_file.dat");
		if ( out_f.fail() )
		{ 
          cout << " Output file opening failed ...\n" ;
		  exit (1) ;
		}


}

void copy ( ifstream& input_file , ofstream& output_file )

{
    char symbol;
    int sum,count;
	double average ;

  while ( ! input_file.eof() )
  {
    

	input_file.get(symbol);
	while ( ! isdigit(symbol) )

	{
		output_file.put(symbol);
		input_file.get(symbol);
	}

	sum=0;
	count=1;
	 while (symbol !=('\n')) 

	  {	output_file.put(symbol);

		if (isspace(symbol))
		
			count = count + 1 ;
			
		if  (isdigit(symbol))

			sum = sum + symbol - 48;

		input_file.get(symbol);
	  }

	 
	   output_file<< "   (** sum= "<< sum << ", count: " << count ;

	output_file.setf(ios::fixed);
	output_file.setf(ios::showpoint);
	output_file.precision(2);

	average = double(sum) / count ;
	output_file << ", average: "<< sum << " / " << count      << " = " << average 
		        << " **) "<<endl<<endl ;
	
  }

**Magos** · 04-14-2003

well, every thing worked fine except for the average

The average is calculated by adding all the values together then dividing by the number of values added.

**girlzone** · 04-14-2003

Well it won't work!! becsuse i'm using the put and get functions!!!

i.e: i'm taking every character and add it to the previous one therefore i have strange numbers ... what can i do??

**XSquared** · 04-14-2003

Try (double)sum / (double)count instead.

**alpha** · 04-14-2003

actually, since you said that the grades are whole numbers in the file, why subtract 48.

sum += symbol . and you also check if it is a digit. so just add, then / by count. not sure if you want to increment count for every space. try incrementing when adding a grade.

**girlzone** · 04-14-2003

ok.. my program works if the grades are from 0-9 else no!! (i'm writing like a program

....

( sum=0 ) what if the first grade was 12 the program will check if 1 is a digit then it will sum it with 0, after that it will check 2 and sum it with 1 .so the sum will be 3 and this is wrong. i want the program to take 12 as whole and sum it to 0...

what should i do ??

**elad** · 04-14-2003

take advantage of the properties of the istream >> operator. >> will terminate input at any whitespace, of which the space character is one example. It will also put the information it reads into any primitive type like char, C style string, int, double, and float without you needing to do a thing, other than declaring appropriate variables to store the information in. And since ifstreams are derived from istreams the >> operator is available to them as well. Forget about all that put/get stuff and ASCII conversions, etc. It's not needed here, unless your instructions were to use it specifically as a learning tool.

You already know that each line will have exactly the same number of entries. You don't know how many lines there is, nor what the values for each name and score will be. so you will probably need one loop with a second loop embedded in it.

>> last name
<< last name
>> first name
<< first name
>> score
<< score
total += score
repeat these three lines nine times
calculate average
<< average
go to next line.

beware that the eof() function when used as a conditional is likely to overread your file by one line causing some erroneous output for the last line of the output file. There are many discussions of this phenomenon on the board so I won't redo them here.

**DirX** · 04-14-2003

Your basic flaw is that you take evrything, name and grades, as characters. For the names this will not give you any trouble but for the grades it will only get you the first out of two possible numbers. The best option would therefor be to have two character variables BufferOne, BufferTwo. You then, for the name, get into BufferOne and output that variable into the next file till you get to the grades. Once at the grades you get one value into BufferOne then you get one into BufferTwo, you then check if BufferTwo is a space. If it is a space you do the following:

Code:

sum = sum + (int)BufferOne;

if it is not a space we can assume it is the second digit of the number so the following code would apply:

Code:

sum = sum + ((int)BufferOne) * 10) + (int)BufferTwo;

you would then eat the space using a get(BufferOne) and start over again getting the first number into BufferOne. THis method would involve quite a lof of if statements and some looping.

**DirX** · 04-14-2003

I was bored so here would be a basic rewrite of your copy function, please do note that i did not feel like debugging it so there might be some elementary mistakes in there like typo's etc, you should be able to pick em outta there.

Code:

void copy ( ifstream& input_file , ofstream& output_file )
{
    	char symbol = '\0';
    	char Buffer = '\0';
    
    	int sum, count;
	double average ;

  	while ( ! input_file.eof() )
  	{
    

		input_file.get(symbol);
		while ( ! isdigit(symbol) )
	
		{
			output_file.put(symbol);
			input_file.get(symbol);
		}
	
		sum=0;
		count=1;
	
		while(symbol != '\n')
		{
			output_file.put(symbol);
			input_file.get(symbol);
			
			if(isspace(symbol))
				count = count + 1;
				
			else if(isdigit(symbol))
			{
				input_file.get(Buffer);
				
				if(isdigit(Buffer))
				{
					sum = sum + ( (int)symbol * 10 ) + (int)Buffer;
					input_file.get(symbol);
				}
				
				else
					sum = sum + ( (int)symbol );
			}
		}
			
			
	
		 
		output_file<< "   (** sum= "<< sum << ", count: " << count ;
	
		output_file.setf(ios::fixed);
		output_file.setf(ios::showpoint);
		output_file.precision(2);
	
		average = (double)sum / (double)count ;
		output_file << ", average: "<< sum << " / " << count      << " = " << average 
			        << " **) "<<endl<<endl ;
		
}

**girlzone** · 04-15-2003

hello

i used another way in the copy function and i asked my teacher to use this way and she said it is ok... The problem is ( i think ) how to move from one line to another after copying it from the input file and adding the average to it???? this is my function i know it looks stupid but what can i do???

Code:

void copy ( ifstream& input_file , ofstream& output_file )

{
    char    first_name[20] , last_name[20] ;
    int       sum,num1,num2,num3,num4,num5 ;
	int num6,num7,num8,num9,num10;
   double    average ;

  while ( ! input_file.eof() )
  {
     

	   input_file >> last_name ;
                   output_file << " " << last_name ;

                    input_file >> first_name ;
	   output_file << " " << first_name ;

	   input_file >> num1  ; output_file << " " << num1  ;
	   input_file >> num2  ; output_file << " " << num2  ;
	   input_file >> num3  ; output_file << " " << num3  ;
	   input_file >> num4  ; output_file << " " << num4  ;
	   input_file >> num5  ; output_file << " " << num5  ;
	   input_file >> num6  ; output_file << " " << num6  ;
	   input_file >> num7  ; output_file << " " << num7  ;
	   input_file >> num8  ; output_file << " " << num8  ;
	   input_file >> num9  ; output_file << " " << num9  ;
	   input_file >> num10 ; output_file << " " << num10 ;
	   
	output_file.setf(ios::fixed);
	output_file.setf(ios::showpoint);
	output_file.precision(2);

	sum = num1 + num2 + num3 + num4 + num5 + num6 + num7 + num8 + num9 + num10;
	average = double(sum) / 10 ;
    output_file << " Average = " << average << endl << endl ; 

	

	 	
  }   
}

**girlzone** · 04-15-2003

hello

i used another way in the copy function and i asked my teacher to use this way and she said it is ok... The problem is ( i think ) how to move from one line to another after copying it from the input file and adding the average to it???? this is my function i know it looks stupid but what can i do???

Code:

void copy ( ifstream& input_file , ofstream& output_file )

{
    char    first_name[20] , last_name[20] ;
    int       sum,num1,num2,num3,num4,num5 ;
	int num6,num7,num8,num9,num10;
   double    average ;

  while ( ! input_file.eof() )
  {
     

	   input_file >> last_name ;
                   output_file << " " << last_name ;

                    input_file >> first_name ;
	   output_file << " " << first_name ;

	   input_file >> num1  ; output_file << " " << num1  ;
	   input_file >> num2  ; output_file << " " << num2  ;
	   input_file >> num3  ; output_file << " " << num3  ;
	   input_file >> num4  ; output_file << " " << num4  ;
	   input_file >> num5  ; output_file << " " << num5  ;
	   input_file >> num6  ; output_file << " " << num6  ;
	   input_file >> num7  ; output_file << " " << num7  ;
	   input_file >> num8  ; output_file << " " << num8  ;
	   input_file >> num9  ; output_file << " " << num9  ;
	   input_file >> num10 ; output_file << " " << num10 ;
	   
	output_file.setf(ios::fixed);
	output_file.setf(ios::showpoint);
	output_file.precision(2);

	sum = num1 + num2 + num3 + num4 + num5 + num6 + num7 + num8 + num9 + num10;
	average = double(sum) / 10 ;
    output_file << " Average = " << average << endl << endl ; 

	

	 	
  }   
}

**elad** · 04-15-2003

Code:

while()
{
  //deal with names for this line
  >> last name
  << last name
  >> first name
  << first name
  //deal with scores for this line
  for()
  {
     >> score
     << score
     total += score
  }
   
   calculate average for this line
   << average
}//go to next line

because >> ignores whitespace such as space character and newline character you will automatically go to the next line once you have read everything in from this line. This technique works great when you know that each line has exactly the same number of fields. It doesn't always work under other conditions however.

NOTE: if you use eof() as the terminating condition for the while loop in this psuedocode there will likely be a duplication of the last line of the input file in the output file. This bug is handled extensively on the board under other posts. Do a search using file handling, or eof() as the search term and I'm sure you will find some of them.

**girlzone** · 04-15-2003

ok DirX, i have tried your function but the output wasn't right!!!
elad, how can i go to the new line ??? it doesn't work!!! and if eof() isn't good in this case what am i suppose to use ?? i know nothing else!!!

**girlzone** · 04-15-2003

hello

i have tried my last code again and guess what ?? it worked except that i have an extra line in the output file and that line contains the same grades as well as the average for the last student ...why is this happening is it because the eof() ??? i don't get it !!

**Brighteyes** · 04-15-2003

why is this happening is it because the eof() ??? i don't get it !!

This is what happens, the principle is exactly the same.

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