Passing 2d Array to function?

Marcosm64 · 04-05-2003

I am triying to pass a 2d Array to a function, but I dont know how, can someone help? here is my code:

Code:

#include <iostream>
using namespace std;

void PrintBoard(int* TheBoard, int Rows, int Columns); 

int main()
{
	int Board[5][5];
	int i = 0, j = 0;

	for (i = 0; i < 5; i++)
	{
		for (j = 0; j < 5; j++)
			Board[i][j] = '\0';
	}

	Board[2][2] = 5;

	PrintBoard(Board, 5, 5);

	return 0;
}

void PrintBoard(int* TheBoard, int Rows, int Columns)
{
	int i = 0, j = 0;

	for (i = 0; i < Rows; i++)
	{
		for (j = 0; j < Columns; j++)
			cout << TheBoard[i][j];
		cout << endl;
	}
}

Thanks in advance.

**CheesyMoo** · 04-06-2003

Code:

void PrintBoard(int board[][],int row,int collum)
{
bla
bla
bla
}

Would that work for ya?

**dP munky** · 04-06-2003

like salem said..that wont work, it shouldnt even compile if memory serves

but this should...

Code:

void PrintBoard(int board[][5],int row,int collum)
{
    /* Code */    
}

as long as you define the number of colums so the compiler knows whats going on.....otherwise the compiler doesnt know how to map out your array

**CheesyMoo** · 04-06-2003

I didn't know that.

**dP munky** · 04-06-2003

i didnt either until i got it wrong on a test, and i was trying to explain to the teacher why i put what i put, and he said all that needs to be defined is the colums...simply for the reason, if you had a 1 dimensional array....thats all you have, columns

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