Thread: **STUPID** newbie question...

Hi!

Can anyone plz tell me why the following code does not work?

Code:

class Class2;

class Class1
{
 friend void Class2::func2();

 private:
	void func1(){}
};

class Class2
{
 public:
	void func2(){}
};

I get an error message saying that Class2::func2() is not a member of Class2..!!!???

thanx

Limitations of forward declaration:
- You can only use it if the size of the forwarded declaration is not needed
- You can not access any elements of the forwarded type

Declare Class2 first.

gg

Yes, I am sure that would work. However, there is more...
Take a look at the code below:

Code:

class Class2;

class Class1
{
 friend void Class2::func2();

 private:
	void func1(){}
};

class Class2
{
 public:
	void func2();
};

void Class2::func2()
{
 Class1 c1;
 c1.func1();
}

I get the same error as before, Class1 can't find the function in Class2. How can I solve this??
If I can't, how can I have two classes access each others members?

Declare Class2 first - you don't have to implement it first.

Code:

class Class2
{
 public:
	void func2();
};

class Class1
{
 friend void Class2::func2();

 private:
	void func1(){}
};

void Class2::func2()
{
 Class1 c1;
 c1.func1();
}

gg

Code:

int main()
{
  char* a = "Thanx that works!";
  cout << a;

 return 0;
}

you are declaring an object of a class called Class2 which is the same name as the class, i dont think that you can do that.

maybe you should try this
class2 mpClass2; // instead of 'Class Class2;


class Class1
{
public: // you should always say that it is public r it
//be seen as a private data function or member
friend void Class2::func2();

private:
void func1(){}
};

class Class2
{
public:
void func2(){}
};