Thread: finding already entered number

How do make sure someone doesn't enter the same number more than once?

This code doesn't work. I'm not sure what I'm doing.

Code:

#include <iostream>
using namespace std;

int main()
{

	int number;

	cout << "Enter five numbers, and don't enter the\n"
		 << "same number more than once" << endl;

	for (int i = 0; i < 5; i++)
	{
		cin >> number;
		
		for (int repeat_number = 0; repeat_number < number; repeat_number++)

		if (repeat_number == number)
		{
			cout << "You've already entered that number" << endl;
			i--;
		}
	}


	return 0;

}

here, take a look at this:

Code:

#include <iostream>

int main()
{
	int number, repeat, i, j;
	int array[6];
	
	std::cout << "Enter five numbers." << std::endl;
	
	for(i = 0; i < 5; ++i) {	
		std::cout << "Enter number " << i + 1 << ": ";
		std::cin >> number;
	
		repeat = number;
		array[i] = number;
		
		if(i > 0) {
			for(j = 0; j < i; ++j) {
				if(array[j] == number) {
					std::cout << "Number repeated." << std::endl;
					exit(1);
				}
			}
			array[i] = number;
		}
	}
	
	for(i = 0; i < 5; ++i) {
		std::cout << "Number " << i + 1 << " = " << array[i];
		std::cout << std::endl;
	}
	
	return 0;
}