Thread: how do i get the largest, smallest, first and last values??

As you read the numbers in, keep a record of the highest/lowest values. The first and last are pretty easy to spot, the first one will be the one the user enters first, and the last one will be...

No need to store all the numbers unless you want to. Just create a few variables like these:

int first, last, highest, lowest.

Post some code, so we can see how far you've got, and then we'll be in a better position to help you.

For example, can you get a number from the user ?

Code:

#include <iostream>

int main ( void )
{
  int i,
      highest,
      lowest,
      first,
      last;
  
  if (cin>>first)
  {
    highest = lowest = last = first;
    while (cin>>i)
    {
      // More code needed here.
      // Simply test the current entry with the highest.  If it is bigger,
      // make the highest entry the same value as the current entry.
      // Then do the same kind of thing for the lowest entry.
    }
  }
}

There's a starter for you.

Originally posted by Nikisha
how do i make the user enter the integer soo many times??

--> while (cin>>i)
This loops until a bad read occurs, so if the user keeps entering, the prog will keep running. There are many ways to control a loop though. You could also add a second condition to this while statement, like loop while i is greater than 0.

Originally posted by Nikisha
well here's my program so far:

Code:

#include <iostream>


using namespace std;

int main()
{
	int n, sum, num, last;
	
	cout << "Enter count of entries: ";
	cin  >> n;
	
	sum = 0;
	for (int i = 0; i <= n; i++)
	{
		cout << "enter an integer: ";
		cin >> num;	

		sum = sum + num;
	}
	
	cout << "Sum of integers = " << sum << endl;

	last = num;

	cout << "The last number is " << last << ' ';

	

	
	return 0;
}

so how do i fit in the highest, lowest and first values into this?

Well, getting the first number is easy. Look at where the user enters the first number. Right after that, you'll want to add the code

Code:

first = num.

But here's the problem: because of the loop, first is always getting num, every time the user enters the next number.

So how do we get around this? Well, you could do one of two things. You can either add a if statement in the loop, and checking that

Code:

if (i == 0)
{
//then first gets num
}

OR you could simply place one line of cin>>num before the loop, but then you have to make some change to the loop accordingly.

What about highest/lowest you ask? Well, what you need to do

The first time the user enters a number, your going to treat that number like it's the highest and the lowest (cause you don't know yet), so your going to set your two veriables, highest and lowest, to that first number. (if (i == 0)) Then when the user enters the next number, you need to re-set highest and lowest to the second number ONLY IF num > highest and the same goes with lowest. Get it?

Pretty simply...

For high:
First read in the very first value and place it in the variable high. Now, as you read in the user's input, constantly test if the value currently in high is larger than the value being inputted.

Code:

if(high < num)
     high = num;

So your loop might look something like:

Code:

for (int i = 0; i <= n; i++)
{
    cout << "enter an integer: ";
    cin >> num;
    sum = sum + num;

    if(high < num)
        high = num;

    if (i == 0)
        high = first = num;
}

use the same idea for lowest values