Thread: How do I print from one function?

Code:

/*
This is a simplified outline of my program as it treats the display of
titles and messages: messages are printed from individual modules.  I want
to change the program by printing out all titles and messages from a single
module, calling this function as and when needed during the execution of the
program.
I have difficulty in grasping how this might be done: I want to call this
single print function from different modules and I want to display only one
particular message at each call to the function.
I have two questions:
1.How would I do this by passing a string (character array: char[]) as an
argument?
2.How would I use a pointer to do this?
*/

main()
{
   one();

   two();

   three();
}

one()
{
   printf("\nmessage 1");
}

two()
{
   printf("\nmessage 2");
}

three()
{
   printf("\nmessage 3");
}

Are you looking for something like this:?

Code:

void print_something(const char* something)
{
    printf(something);
}

This is exactly the same:

Code:

void print_something(const char something[])
{
    printf(something);
}

gg

Yes, but I want all three messages to be in the print function & I want to print a different message in turn, calling it from its appropriate function (one, two or three).

clinamen

Thanks for this Hammer, I`ll try it out.

clinamen