In C++ I am trying to display the odd numbers and average the even numbers between two integers.
The following is the code i have thus far...
This is what I have thus far..but cant figure out how to only display the odd numbers...havent begun averaging the even numbers....:
#include <iostream>
using namespace std;
void main (void)
{
int num1, num2, num = 0;
cout << "Please enter the the two numbers" <<endl;
cin>> num1 >> num2;
while (num1++ < num2)
cout <<num1;
if(num1 % 2 ==0)
cout << num1;
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odd and even
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After reading the material provided I am still unable to determine how to display odd numbers between two randomly selected integers.
if you read the odd and even page, you should know. just replace the printf with cout.Originally posted by bmilton
After reading the material provided I am still unable to determine how to display odd numbers between two randomly selected integers.
you don't really even need a fxn.
here is your biggest hint. use %.
edit: you also need to fix your code, and the first two links Hammer posted shall not be taken lightly.
edit2: you have used %. just think about it. you have:
your answer is right there. just think about it. it's not that tough, and the odd and even faq link has the answer.Code:if(num1 % 2 == 0) cout << num1;
Last edited by alpha; 03-03-2003 at 03:31 PM.
This part is very simple. You don't even have to find the even numbers.Originally posted by bmilton
In C++ I am trying to ... average the even numbers between two integers.
If I did your homework for you, then you might pass your class without learning how to write a program like this. Then you might graduate and get your degree without learning how to write a program like this. You might become a professional programmer without knowing how to write a program like this. Someday you might work on a project with me without knowing how to write a program like this. Then I would have to do you serious bodily harm. - Jack Klein
