1. ## Very NEW Beginer, Going mad

Hi, I need to write a program that inputs three integers from the keyboard and prints out the smallest and largest, using only the IF statement with no logical AND or OR.
Now this is surpose to be possable, but when I do it I get the two lowest numbers and the two highest numbers.
Driving me nuts please help. I spent 3 hours going over and over the same stuff and I cant see how to do it without useing more then just IF.

Thanks

Chris.

2. Post your code and we can show you where your mistakes are.

3. Very easy. Not a single boolean operator. You can even make it smaller using the ? : tierinary operator, but its advanced stuff:

( (condition) ? truepart : falsepart )

A function to find the smallest number would use the same principle as this one:

Code:
```int Largest(int a, int b, int c)
{
if (a>b)
{
if (a>c)
return a;
else
return c;
}
else
{
if (b>c)
return b;
else
return c;
}
}```

4. ## Thanks, but..

Its more difficult then that as the challenge I was set said you cant use "else" as well.
If its not possable to do this without "else" then please let me know if it is, I will try yet again to work it out.
Thanks

5. i wrote your program..just a plain if and a for loop

Code:
```#include <iostream>

using namespace std;

int main()
{
int num[3];

cout << "enter first num: ";
cin >> num[0];
cout << "enter second num: ";
cin >> num[1];
cout << "enter third num: ";
cin >> num[2];

int low = num[0]; //low is set to first
for(int i = 1; i < 3; i++) //loop for low
{
if(low >= num[i])
{
low = num[i];
}
}

int high = num[0]; //high is set to first
for(i = 1; i < 3; i++)
{
if(high <= num[i])
{
high = num[i];
}
}

cout << "low is " << low << endl
<< "high is " << high << endl;

return 0;
}```
:P was bored..code kinda long could be shorter...

6. Hope this helps: No if's, no boolean operators.

(condition ? truepart : falsepart)

Code:
`highest=( (a>b) ? ((a>c) ? a : c) : ((b>c) ? b : c) );`

7. Chris,

Between nextus and Speedy5 (nextus' code being more straightforward), your homework is done.

A simple 'copy & paste' and you've learned, probably, little, or nothing. At least, nothing that you'll retain.

Good show, people.

(Do you think that there may just be a reason why the moderators and very senior members suggest that students do their own work?)

-Skipper

8. Agree with Skipper. Let them do there own work first.

9. I agree with skipper.

10. ## ~

Nah, we should write all their programs for them. That way we'll get practice, and they won't learn anything... Less competition for real programmers in the job market later on.

11. haha..very funny...i agree that it is good practice...but i get so caught up in the question..that like a few moments later the whole program is written....i am sorry..i try not to do it again...:P

12. You see, I had the same question at school. People asked me how to do it at school so its only fair if I help this person. Plus, I didn't give the WHOLE answer, he still needs to understand it: I gave him an explanation of the ?: operator.

I'll give more broader help next time!

13. That really didnt do anything for em...if he is just doing basic programming, the teacher will think WTF when he sees that kind of syntax, especially

Code:
`highest=( (a>b) ? ((a>c) ? a : c) : ((b>c) ? b : c) );`
also, i doubt he is allowed to use loops as well, seeing as he has just started conditional statements

14. as basic as it can get without using else's and AND or ORS

Code:
```#include <iostream.h>

int main (void)
{
int num1;
int num2;
int num3;
int max;
int min;

cout << "Enter Number 1: ";
cin >> num1;

cout << "Enter Number 2: ";
cin >> num2;

cout << "Enter Number 3: ";
cin >> num3;

max = num1;
min = num1;

if (num2 > max)
max = num2;

if (num3 > max)
max = num3;

if (num2 < min)
min = num2;

if (num3 < min)
min = num3;

cout << "\nLargest number is: " << max << endl;
cout << "Smallest number is: " << min << endl```

15. well, that makes 3 people that just did someone else's homework in this thread. Read This