Thread: How to Flush standard input?

Hi!

I´m trying to fulsh standard input - all though this seems not possible to me. My code is:

Code:

	bool exit_status;
	char current;

	exit_status=false;
	while(!exit_status){
		cin.clear();
		cin >> current;
		switch(current){
		 case 'p':
			// do something
		 break;
		 case 'u':
			// do something
		 break;
		 case 's':
			// do something
		 break;
		 default:
		 cout << "Unkown command" << endl;
		}
}

When I run this, I don´t expect when typing: "pussy", that the program runs the functions ascossiated with p,u,s,s and types "Unkown command"....

Anyone knows how to flush the inputstream so that only function p will be run???

y not

char variable[1];

now only the first letter is read....and i hope u mean pussy in the feline sense.

Sure I could read the thing into a string, but what I search is a function that will FLUSH unread input. I thought clear(): did that, but it doesn´t... Any suggestions?

cin.clear() clears the flag that would be set if a user entered a character into an integer variable or such.

cin.ignore(80, '\n') *should* do what you want as it *should* strip off everything but your 'p'

What about something like fflush()?