Thread: Is cin for only numbers??

Code:

#include <iostream.h>
char user, pass;

int main(int argc, char *argv[])
{
     cout <<"                          Project Communication Service\n";
     cout <<"                            Private Message bot v1.0\n\n\n";
     cout <<"LOGIN\n";
     cout <<"Username: ";
     cin>>user;
     cout << "Password: ";
     cin>>pass;
  return 0;
}

The above code will only execute the pasword cout and cin if the user cin = a integer, otherwise it just closes. Does anyone know why? (I am really new to C++, sorry) Thanks.

I think you are trying to make a user/pass longer than 1 character. In that case you must use strings, either by the string class or a one dimensional char array.

Code:

#include <iostream>
using namespace std;
int main() /*int argc char *argv[] not needed */ {
char user[51],pass[51];
cout<<"Login"<<endl;
cout<<"pass:"<<endl;
cin>>pass;
cout<<"user:"<<endl;
cin>>user;
return 0;
}

cin works with all built-in data types, including characters.

EDIT: Ohhh RoD beat me

You're asking for single characters, and (veterans can correct my terminology ) if you enter more than one char for "user", the variable will only account for one of the chars and the rest are shifted over to "password". Try this...

Code:

#include <iostream.h>

int main(int argc, char *argv[])
{
	char user[10], pass[10];

	cout <<"                          Project Communication Service\n";
	cout <<"                            Private Message bot v1.0\n\n\n";
	cout <<"LOGIN\n";
	cout <<"Username: ";
	cin >> user;
	cout << "Password: ";
	cin>>pass;
	return 0;
}

Actually now that you mention it, what is the difference between using cin as it is and cin.getline?
I know cin cant read strings with whitespaces (i.e. "this is a test" will only read "this")
Does cin.getline overcome this?

Ok, Thanks alot (both of you).

cin would cut off all but the first letter in the string.

Im pretty sure it doesn't...

Originally posted by Panopticon
Im pretty sure it doesn't...

You're right, it doesn't

Wow, Didn't know so many people posted in this thread, Thanks again. I have one more Q though. Is it possible to make all char's in a cin look like * when typed, Kinda like let hte passChat to * (like in VB)

>>Is it possible to make all char's in a cin look like * when typed
No, you'll need a non-standard function to do non-buffered input.

Will do, Thanks.

I done some experimenting with getline a few moments ago and it seems to behave as expected. But it can be overrun just like gets()
hmmm
What I dont understand are the parameters of getline
the first one is a pointer to the first element of the target array, and the second one is... what? the length of the string?
I tried the following:

Code:

char name[10];
cin.getline(name,10);
cout<<name;
cout<<name[10];

i entered 10 characters and cout<<name produced the first 9 characters i entered. name[10] produced a garbage result. It was not a null terminator so thats where im confused about the implementation of getline().