Thread: Noobie question

I am just using it??

you can just use it like

Code:

 
 isdigit(1);

it will return a 0.

but............. the user is entering some number which i have defined as choice and i want choice to be evaluated not 1

Then you change the 1 to the variable you want tested
You sure you read the tutorial i posted?

Jesus, I don't mean to sound mean... but it's not our job to teach you the language. Read a tutorial or something. http://www.cprogramming.com/tutorial.html

You have MANY errors in your code. Remove the declaration for isdigit at the top of your program.

Change x = x++; to x++;
remove x = x;

Code:

cin >> choice;

isdigit(choice)

if (dig==0)

Change that to

Code:

 
cin >> choice;

if (isdigit(choice))

And finally, remove the depricated headers <iostream.h> and <ctype.h>
Use <iostream> and <cctype> instead.

So, the top of your program should look like this:

Code:

#include <iostream>
#include <conio.h>
#include <cctype>
using namespace std;

I'm sure there are others, but I quickly looked at your code and those are the ones which stood out.

my code includes isdigit(choice) but the page u referred me to is multiplying two numbers together not asking for a number, evaluating whether the input is really a number, and then and then doing something based on what number was entered, or otherwise re-asking for a number...so like I really dont know what to do

Now the below code will compile, however the screen wont remain up and if i input e it will not do what i want it to do, which is ask me to input until i input 1 or 2

Code:

#include <iostream.h>
#include <conio.h>
#include <ctype.h>

int main()
{

 int choice=0;
  int room;
  int x=0;
  int dig=isdigit(choice);

  cout<<"Please choose a room (1 or 2): ";

  cin >> choice;

  isdigit(choice);

  if (dig==0)

  cin >> choice;

  else

  while(x==0)

 {

if(choice==1)
x=x++;
else if(choice==2)
x=x++;
else
x=x;        		
  } 				

  if(choice==1)				

  {

  		room=1;
     cout<<"You enter a room\n";    

  }

  else if(choice==2)		

  {
  		room=2;

     cout<<"You are in room 2\n";		

  }

  else

  {

    cout<<"You should not see this.\n";

  }

  if (room==1)
  {
  cout<<"Yep";
  }
  else if (room==2)
  {
  cout<<"Nope";
  }
  else
  {
  cout <<"I need to know how to ask them to plz enter a proper room choice, but how to do that? i don't know.";
  }

  return 0;

}

No, it won't remain up indeed, put it in a loop.

And the below code here if i enter 3 or e it stops responding instead of asking me to input again

#include <iostream.h>
#include <conio.h>
#include <ctype.h>

int main()
{

int choice=0;
int room;
int x=0;

cout<<"Please choose a room (1 or 2): ";

cin >> choice;

if (isdigit(choice))

cin >> choice;

else

while(x==0)

{

if(choice==1)
x++;
else if(choice==2)
x++;
else
x=x;
}

if(choice==1)

{

room=1;
cout<<"You enter a room\n";

}

else if(choice==2)

{
room=2;

cout<<"You are in room 2\n";

}

else

{

cout<<"You should not see this.\n";

}

if (room==1)
{
cout<<"Yep";
}
else if (room==2)
{
cout<<"Nope";
}
else
{
cout <<"I need to know how to ask them to plz enter a proper room choice, but how to do that? i don't know.";
}

return 0;

}

change this

Code:

 if (isdigit(choice))

into this

Code:

 if (isdigit(choice)!=0)

And in the below code-which I believe does contain a loop-isnt that what while is? - it wont compile because it said i never use x but i DO use x

Code:

#include <iostream.h>
#include <conio.h>
#include <ctype.h>

int main()
{

 int choice=0;
  int room;
  int x=0;

  cout<<"Please choose a room (1 or 2): ";

  while(x==0)

    cin >> choice;

if (isdigit(choice))

  cin >> choice;

    else

 {

if(choice==1)
x++;
else if(choice==2)
x++;
else
x=x;        		
  } 				

  if(choice==1)				

  {

  		room=1;
     cout<<"You enter a room\n";    

  }

  else if(choice==2)		

  {
  		room=2;

     cout<<"You are in room 2\n";		

  }

  else

  {

    cout<<"You should not see this.\n";

  }

  if (room==1)
  {
  cout<<"Yep";
  }
  else if (room==2)
  {
  cout<<"Nope";
  }
  else
  {
  cout <<"I need to know how to ask them to plz enter a proper room choice, but how to do that? i don't know.";
  }

  return 0;

}

And with this code it works fine if i enter 1 or 2 but once again with e or 3 it stops responding

Code:

#include <iostream.h>
#include <conio.h>
#include <ctype.h>

int main()
{

 int choice=0;
  int room;
  int x=0;

  cout<<"Please choose a room (1 or 2): ";

      cin >> choice;

if (isdigit(choice)!=0)     

  cin >> choice;

    else

  while(x==0)



 {

if(choice==1)
x++;
else if(choice==2)
x++;
else
x=x;        		
  } 				

  if(choice==1)				

  {

  		room=1;
     cout<<"You enter a room\n";    

  }

  else if(choice==2)		

  {
  		room=2;

     cout<<"You are in room 2\n";		

  }

  else

  {

    cout<<"You should not see this.\n";

  }

  if (room==1)
  {
  cout<<"Yep";
  }
  else if (room==2)
  {
  cout<<"Nope";
  }
  else
  {
  cout <<"I need to know how to ask them to plz enter a proper room choice, but how to do that? i don't know.";
  }

  return 0;

}

You seriously need to take some tutorials, that code is a mess,
and half of it wont work. Plz learn the tutorials provided on this
website.

I know...i was hoping you would say why it is a mess-the tutorials dont exactly show how to do this...