Thread: Inserting string

Let's say I have a string (the current line in an array)

And the user want to insert a new string into a certain position of that string ... say... after the 5th character.

Can I use strncopy (CopyTo, CopyFrom, Numcells)
OR strncpy (Append To, AppendFrom, Numcells) ??

What is "Numcells" suppose to be, the position of where to insert the new string?

This is what I tried

Code:

......

 cout <<"Where on the current line"; 
 cout<<"do you want to insert a new string?"<<endl;
 cin>> position;                          
 cout<<"enter the string to be inserted: "<<endl;
 cin.getline(temporary_array[0], 80, '\n');
 strncpy (array[i-1],temporary_array[0],position);
 
		
cout<<"The current line is now: "<<array[i-1]<<endl;

.....

First of all, the whole program just exits as soon as it reaches "enter the string to be inserted"
But if I have this:

Code:

 cout<<"enter the string to be inserted: "<<endl;
 cin.getline(temporary_array[0], 80, '\n');
 strncmp (array[i-1],temporary_array[0],6);

 cout<<"The current line is now: "<<array[i-1]<<endl;

It just overwrites the first 5 characters of the original line.
I shouldnt be using strncpy() or what?

Code:

#include <iostream>
#include <string>

using namespace std;

int main()
{
	string str1("The first string");		
	string str2("and second ");

	str1.insert(10, str2);

	cout << str1 << endl;

	return 0;
}

Well - judging from your post your not actually using string objects - so this may be adding something into the mix that you are not interested in trying. But the string object contains a rather easy to use insert() method. You could perhaps use an array of strings?

strncmp() is used for comparing character arrays - not for appending them. That would be strcat().

You can do something like this using the cstring functions:

Code:

#include <iostream>
#include <cstring>

using namespace std;

int main( void )
{
   char input[100] = "Cats are nice usually";
   cout << "Before: " << input << endl;
   strncpy( input, "Dogs", 4 );
   strncpy( input + 9, "mean", 4 );
   cout << "After: " << input << endl;

   return 0;
}

NP...

j=0;

for(i=0; i < loc-1; i++)
temp[j++] = user1[i];

// copy user1 array into temp ?

yep.. copy elements 0-loc. But remember the array is indexed one less than your user requested for the entry point, so subtract 1 from your user's request.

for(i=0; user2[i] != '\0'; i++)
temp[j++] = user2[i];

// copy user2 array into temp?? Then i look at the next loop and
think, that can't be it.

yep that's exactly what it did. You have left user1 at the desired location, so now you can copy the contents of user2 into temp, but maintain temp[j++] so that you keep its placement for the next operation

for(i=loc-1; user1[i] != '\0'; i++)
temp[j++] = user1[i];

No biggie here... You know where you left of in user1 with the variable loc. All you need to do is to start the copy process at that point you left off in until you encounter the null terminator of '\0' in user1. Just remember to terminate temp when the process is done. That's what temp[j] = '\0'; does

HTH