Thread: union problems return

ok let say i have a union called "shareLD" which takes this form:

Code:

union shareLD
{
   double dval;
   long lval;
};

shareLD myUnion;
myUnion.dval = 3.5;

so now dval contains 3.5...i get that part...but does lval contain 3.0 since they share the same memory?

You can use both members at same time. The problem here is that double is not an int-type. If you had for example the following union:

Code:

union myunion
{
    int a;
    int b;
};

Now if you have a variable of type myunion and assign a value x to variable a, then b has the same value as a. They share the same memory.