Thread: A Class question

But those variables would be local and not global. So only the function that they were created in should be able to use them. I am not sure if this is correct but it seems logical.

You can create a global class?
A class that every function can acces?

I can't answer that question, I don't know anything about classes. But I know you create a global variable by creating it out of a function. But global variables can create run-time errors.

Originally posted by Travis Dane
You can create a global class?
A class that every function can acces?

No, you create a global object.

The answer to this isn't very hard...
Ask this; what if you want to access the value of a single integer in two different functions, what do you do? One of many things.

Originally posted by Munkey01
I don't know anything about classes

You're not worthy of your avatar!

I know some about them in Ruby but not enough to call me a user of classes. I stay away from them when coding in Ruby. But I have not come accross them in C++ yet.

Originally posted by Eibro
No, you create a global object.

The answer to this isn't very hard...
Ask this; what if you want to access the value of a single integer in two different functions, what do you do? One of many things.

Sorry,meant to say object.

As to the ask, you create a global int or pass it from the point
where they are called from, but thats not possible with classes

Originally posted by Travis Dane
Sorry,meant to say object.

As to the ask, you create a global int or pass it from the point
where they are called from, but thats not possible with classes

Why not? Have you tried it?

Well yes, like so

Code:

class abc
{
abc();
int a;
}

abc::abc()
{
}

abc def; // like NOT allowed, it doesnt recognize abc

void main()
{
cout << def.a;
}

Code:

class abc
{
public:
abc();
private:
int a;
};

abc::abc()
{
}

abc def;

I spot three immediate errors
No semi-colon after class definition
Constructor is private
And that's not a valid main() function

Also, I doubt a global variable is the best answer to your problem.

All 3 errors you spotted was because i typed it out of my hand,
I need to acces a variable in a object thats given a value from
another function, got a solution?

Pass the object by reference to both functions.
Also, it's perfectly valid to do what you did in your previous post; you must have made an error somewhere else.

Really? my compiler doesn't think so!
Could you post your code for me to try then?

Code:

class Buffer
{
public:
   Buffer(size_t size) : m_data(new char[size]), m_size(size) 
   {
         memset(reinterpret_cast<void*>(m_data), 0, size);
   };

   size_t length() const { return m_size-1; }
   char * data() { return m_data; }

   ~Buffer() { delete[] m_data; }

protected:

   Buffer(const Buffer &bf) {};
   Buffer &operator=(const Buffer &bf) {};

   char *m_data;
   size_t m_size;
};

// ...

Buffer myBuf(512);

void ReadData();
void PrintData();

int main()
{
   ReadData();
   PrintData();

   return 0;
}

void ReadData()
{
   cin >> myBuf.data();
}

void PrintData()
{
   cout << myBuf.data();
}

OR, as I suggest... pass the object by reference.

Code:

void PrintData(const Buffer &bf);
void ReadData(Buffer &bf);

int main()
{
   Buffer myBuf(512);

   ReadData(myBuf);
   PrintData(myBuf);

   return 0;
}

void ReadData(Buffer &bf)
{
   cin >> bf.data();
}

void PrintData(const Buffer &bf)
{
   cout << bf.data();
}