Thread: function insanity

omg this is driving me nutz!!!!!!!

i want to make this code into a function...

#include <stdio.h>
#include <iostream.h>

int main(int argc, char *argv[])
{
printf("%S",argv[0]);
cout<<argv[0]<<endl;
return 0;
}

i have tried hundreds of ways and i am about to go insane!!!!!!!!!

this is one of my many pittifull atempts!!!!!

char Findname()
{
printf("%S",argv[0]);
cout<<argv[0]<<endl;
return argv[0];
}

give this a try

Code:

#include "stdafx.h"
#include <iostream> 
using namespace std;

void printArgs( int nNumOfArgs, char * szArgs[] );

int main(int argc, char *argv[]) 
{

	printArgs( argc, argv );

	return 0; 
} // end

void printArgs( int nNumOfArgs, char * szArgs[] )
{

	for( int i = 0; i < nNumOfArgs; i++ )
	{
		cout << szArgs[ i ] << endl;
	}

}

do i really have to make that complicated?
all i want is a function that i can call that gives the location and name of the program currently running...

anyways thx for your help

Well give this a try

Code:

#include "stdafx.h"
#include "windows.h"
#include <iostream> 
using namespace std;

int main() { 
	
	char szFileName[ MAX_PATH + 1] = {0};
	GetModuleFileName( NULL, szFileName, MAX_PATH+1 );
	
	cout << szFileName << endl;

	return 0; 
} // end