typing effect on text

**painkiller05** · 09-02-2006

it does not run on my turbo c. i got too many errors.

**twomers** · 09-02-2006

And the errors say???

**painkiller05** · 09-02-2006

Undefined symbol 'text'
Undefined symbol 'msg'
Undefined symbol 'msg1'
Extra parameter in call to TypeText()

**twomers** · 09-02-2006

Copy and paste this to your thing

Code:

#include<iostream>
#include<string>

#include<windows.h> // for Sleep

using namespace std; 


/*
#define stiring string
// Sorry

void TypeText ( stiring text ) // typo, but I'm refusing to admit it! string text
*/


void TypeText( string text )
{
   for ( int i=0; i<(int)text.size(); i++ )
   {
      cout<< text[i];
      Sleep( 50 );
   }
}

int main()
{
	string msg = "This is only a test.";
	string msg1 = "I hope that this will work.";

	TypeText ( msg );
	TypeText ( msg1 );


	return 0;

}

**dwks** · 09-02-2006

Code:

void TypeText ( stiring text )

Undefined reference to `stiring'

Code:

for ( int i=0; i<(int)text.size(); i++ )

Rather than cast to an int, you could make i the same type.

**twomers** · 09-02-2006

Originally Posted by dwks

Code:

void TypeText ( stiring text )

Undefined reference to `stiring'

Code:

for ( int i=0; i<(int)text.size(); i++ )

Rather than cast to an int, you could make i the same type.

ah, i forgot the #define stiring string line. Whoops, my bad. Calling it an int, and casting is less writing, dwks

**dwks** · 09-02-2006

Yes, but it isn't much harder to use

Code:

for(string::size_type i; i < text.size(); i ++

now is it?

**twomers** · 09-02-2006

I agree. I use it sometimes, but I can never remember where the _ goes in it, or even if there is one there, so if I'm doing it from memory, I (cast).

that size_type always confused me though. Why doesn't .size() just return an int?

**ZuK** · 09-02-2006

Originally Posted by twomers

that size_type always confused me though. Why doesn't .size() just return an int?

Guess it's an unsigned type because negative sizes don't make sense.
Kurt

**painkiller05** · 09-02-2006

how come your program not work on my turbo c++? :-/

**dwks** · 09-02-2006

Because a size_type is probably an unsigned long, but it could be bigger. I don't know about C++, but in C a size_t is the largest unsigned type supported by the compiler, even if that type is non-standard like _uint64. If you have a really long string you might need something like that.

It's like fseek() and ftell() in C. They use int positions. Well, guess what? The C99 functions fgetpos() and fsetpos() do exactly the same thing, but using an fpos_t variable, which can hold much larger values. (Yes, there really are files larger than 2GB.)

**zx-1** · 09-02-2006

Iterators!

Code:

for (string::iterator i = str.begin(); i < str.end(); i++)
{
    cout << *i << flush;
    usleep(500000);
}

**dwks** · 09-02-2006

Did you change stiring to string?

**twomers** · 09-02-2006

Originally Posted by ZuK

Guess it's an unsigned type because negative sizes don't make sense.
Kurt

Good point. But it's got its own type, right string::size_type ... I'll test out using all sorts of unsigned things tonight I think, just to see if I can get it not to warning me.