Thread: more questions!!

since my teacher is being... dumb... I thought i ask here

Code:

   while(pickenemy != picking){
      infile >> enemy_name;
      picking ++;
   }
   fighting = true;
   infile >> enemy[LVL];
   infile >> enemy[STR];
   infile >> enemy[AGL];
   infile >> enemy[INT];
   infile >> enemy[MP_MAX];
   infile >> enemy[HP_MAX];
   infile >> enemy[LM];

   enemy[MP_CRT] = enemy[MP_MAX];
   enemy[HP_CRT] = enemy[HP_MAX];

Wood_Pecker
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do infile automatically go to the next line when it reads the integers? Why did it displays 0x00000000 when i put a cout in front of infile >> enemy[LVL];?

Since >> returns a confirmation code of the read operation, not the data.

Every time you use infile it goes to the next line... well that is in my experiance and thats how i do it in my game

Code:

cout << "\n\nWhat is your name: (type exit to go back to the menu): ";
  cin >> filename;
  if(strcmp(filename,"exit")!=0) 
  {
  infile.open(filename);
  if (!infile)
   {
    clrscr();
    cout << "\n\nThat is not a valid character. Please try again.\n\n";
    Sleep(2000);
    return main();
   } 
   else if (infile.good())
   {


  infile >> user.name;
  infile >> user.nextskill;
  infile >> skill.skillneed;
  infile >> user.skill;
  infile >> user.money;
  infile >> user.hp;
  infile >> user.armor;
  infile >> user.health;
  infile >> user.maxdam;
  infile >> user.mindam;
  infile >> user.skillpoints;
  infile >> lvl.setone;
  infile >> lvl.settwo;
  infile >> lvl.setthree;
  infile >> lvl.setfour;
  infile >> lvl.setfive;
  infile >> it.amulate;
  infile >> it.fpotion;
  infile >> it.glow;
  infile >> it.potion;
  infile >> it.ring;
  infile >> it.shield;
  infile >> it.sword;