Thread: c++ code a destructor to delete the dynamically allocated array!!!

In my code I have to define a class called Array, it simulates a dynamic array of integers and I also have to code a constructor. This all seems to work fine, but I also have to code a destructor that will delete the dynamically allocated array, this is where I run into problems. This is the code that I have.

Code:

____________________________________________________
class Array
{
	private:
		int size;
		int *pointer;
		
	public:
	   Array()
	   {
	       size=0;
                       pointer=NULL;
	  }

	void load()
	{
	    cout <<"Enter the number of integers in the array.\n\n";
	    cin >>size;
	    pointer = new int[size];
	    int i;
	    for (i=0; i< size; i++)
	    {
	        cout <<"Enter interger # " << i+1 <<"\n";
	        cin >>*(pointer+i);
				
				
	   }
                 }//end of load

	void print()
	{	
	   int i =0;
	   cout <<"The array contains " <<size << "integers.\n\n";
	   cout <<"They are:\n";
	    while (i < size)
	       {
	           cout <<i+1<<")\t"<<*(pointer+i)<<endl;
	            i++;

	       }//end of loop

	  }

	~Array()        //destructor to delete the array
	{
		delete []pointer;
	}

};

void main (void)
{
	Array array1;
	array1.load();
	array1.print();
	array1.~Array();
	

	
}

__________________________________________________

It runs fine when I comment out the destructor, but with it in my program crashes after it displays the integers in the array. Any help would be great. Thanks

you should call

delete array1;

but as was previouslt said, it doesn't really matter because the program exits right after it anyway, so the memory will be deallocated without calling anything.

but in most programs you should use delete, it will call the deconstructor properly.

oh yeah, sorry I wasn't really paying attention.