
The Josephus Problem
I am having a bit of trouble. The Josephus problem is where you have a circle of people, body_count people big (like, if body_count were 5, that means the circle is made up of 5 people). And another term, excuse_counter, is set to a number. Using this number we go around the circle elinimating people until one is left.
For instance, let's say the circle is made of 9 people, and we choose our excuse_counter to be 5:
5, 1, 7, 4, 3, 6, 9, 2, 8
We reloop around this circle nailing off the person we come to when we count to excuse_counter. Using the remaining people we count again, etc, until we are left with one man left.
However I am having a bit of trouble with the coding portion. It finds the first person alright, but from here it's all downhill:
Code:
person* pick_person(person *group, int excuse_counter, int body_count){
person *temp = new person;
temp > position = 12345;
temp > next = group;
person *previous = temp;
person *current;
for (int i = 1; i < body_count; i++){
for (int x = 1; x <= excuse_counter; x++){
if (temp > next > next == NULL)
temp > next = previous > next;
else
temp = temp > next;
}
cout << "\nPerson " << temp > position << " is leaving...";
current = temp;
while (previous > next != current){
previous = previous > next;
}
previous > next = current > next;
delete current;
}
return group;
} //end person *pick_person
The struct:
Code:
struct person{
int position;
person *next;
};
I know this is very close to working but it needs a push in the right direction. I am using a linklist

I would use a queue. I had to do this problem in college.
Also, would it be better to use a random number to choose which person who would be killed??

No the user decides the values

That and the problem states that we must use a linklist

well my approach to this would be a circular list. This can be rotated and nodes removed. I would think that a circular list will model a circle of people better

Try to find the trick to solving this problem fast without a
list.