Thread: pointers as function arguments

I am using a pointer to a double as an argument for a function that prints out the memory address, contents and name of the variable that the pointer points to, but I can't figure out how to output the name of the variable that the pointer points to.

Here is the code:

Code:

#include <iostream>
 #include <string.h>

 void iaddress(double* num);

 int main()
 {
	 double num1 = 1.23;
	 double num2 = 100.75;
	 char *str1 = new char[26];
	 strcpy(str1, "Pointers are interesting!");
	 double num3 = -35.5;
	 double *ptr4 = new double;
	 int i = 0;

	 // str1 output
	 cout << "str1 - main: address: "  << &str1 << " contents: " << str1 << endl;

	//	num1 output and function call
	 cout << "num1 - main: address: " << &num1 << " contents: " << num1 << endl;
	 ptr4 = &num1;
	 iaddress(ptr4);

	//	num2 output and function call
	cout << "num2 - main: address: " << &num2 << " contents: " << num2 << endl;
	ptr4 = &num2;
	iaddress(ptr4);

	//	num3 output and function call
	cout << "num3 - main: address: " << &num3 << " contents: " << num3 << endl;
	ptr4 = &num3;
	iaddress(ptr4);

	//	ptr4 output and function call
	cout << "ptr4 - main: address: " << ptr4 << " contents: " << *ptr4 << endl;
	*ptr4 = 123.4;
	iaddress(ptr4);


	delete ptr4;
	delete [] str1;



	 return 0;

 }

 //	FUNCTION HEADER AND CODE

 void iaddress(double* num)
 {
	cout << "	" << num << "- main: address: " << num << " contents: " << num << endl;
	delete num;
 }

Thanks for any help.

Brian