Thread: How to you loop this?

I did the first example using two for loops. However it come out
123454321 and not

1
2
3
4
5
4
3
2
1 but you can just format that.

Code:

#include <iostream>
#include <conio.h> // for getch

using namespace std;

int main ()
{
    int i;

    for (i = 1; i<= 5; i++) // loop to get 12345
    {
    cout <<i;
    }
    for (i = 4; i>=1; i--) // loop to get 4321
    {
    cout <<i;
    }
    getch(); //ignore this for my compiler
    return 0;
}

IM just not exactly sure how to get 1
12
123
But this is a start i guess

Here a small example using printf:

Code:

#include <string.h>

int main(void)
{
   int i;
   char msg[] = "12345";
   int l = strlen(msg);

   for(i = 1; i < l; i++) printf("%.*s\n", i, msg);
   for(i = l; i > 0; i--) printf("%.*s\n", i, msg);
   return 0;
}

hmm.. i know how to get the first half of the first problem

Code:

for (a = 2; a < 7; a++)
  {
     for (x = 1; x < a; x++)
      {
        cout << x;
      }
    cout << endl;
  }

i know there is a way to write the entire problem 1 in nested loops.. i just did it not but a week ago.. but it seems to have fled my brain.. bummer...

this set of code produces the following output

Code:

1
12
123
1234
12345

printf() is valid in C as well as C++. (here is no cout in C.) Check out sprintf() too.

PLEASE HELP I'm not asking your guys to do my work. BUt atleast give me some hint some instruction to do those while loops

thz