Thread: why won't this work

  1. #1
    Registered User
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    why won't this work

    Code:
    # include <iostream>
    # include <cmath>
    using namespace std;
    
    int average, sd, s1, s2, s3, s4, deviation;
    
    int main()
    {
    	cout << "Press enter after entering a value.\n";
    	cout << endl;
    	cout << "Enter score one: ";
    	cin >> s1;
    	cout << "\nEnter score two: ";
    	cin >> s2;
    	cout << "\nEnter score three: ";
    	cin >> s3;
    	cout << "\nEnter score four: ";
    	cin >> s4;
    	cout << "\nThe average of your four scores is "<<average<<".\n";
    	cout << "The stand deviation of your scores is "<<sd<<".\n";
    
    	average =(s1+s2+s3+s4)/4;
    	deviation =(((s1-average)*
    		(s1-average))+((s2-average)*
    		(s2-average))+((s3-average)*
    		(s3-average))+((s4-average)*
    		(s4-average)))/3;
    	sd = sqrt(deviation);
    
    	return 0;
    }
    &#91;code]&#91;/code]tagged by Salem

  2. #2
    Banal internet user
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    Here.... look at the difference, and think about it, I think you'll figure it out
    Code:
    # include <iostream>
    # include <cmath>
    using namespace std;
    
    int average, sd, s1, s2, s3, s4, deviation;
    
    int main()
    {
        cout << "Press enter after entering a value.\n";
        cout << endl;
        cout << "Enter score one: ";
        cin >> s1;
        cout << "\nEnter score two: ";
        cin >> s2;
        cout << "\nEnter score three: ";
        cin >> s3;
        cout << "\nEnter score four: ";
        cin >> s4;
    
        average =(s1+s2+s3+s4)/4;
        deviation =(((s1-average)*(s1-average))+((s2-average)*(s2-average))+((s3-average)*(s3-average))+((s4-average)*(s4-average)))/3;
        sd = sqrt(deviation);
    
        cout << "\nThe average of your four scores is "<<average<<".\n";
        cout << "The stand deviation of your scores is "<<sd<<".\n";
    
        return 0;
    }

  3. #3
    geek SilentStrike's Avatar
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    You are outputting the values before you are computing them for one. Second, you probably want to use doubles for the average and standard deviation (if not all the inputs as well) so they can have decimals.
    Prove you can code in C++ or C# at TopCoder, referrer rrenaud
    Read my livejournal

  4. #4
    Banal internet user
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    lol, look at his code again Inquirer.... see the error?

    Oh, and yea... good idea SS

  5. #5
    geek SilentStrike's Avatar
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    You can use cin to get pretty much every basic type (perhaps not bools).
    Prove you can code in C++ or C# at TopCoder, referrer rrenaud
    Read my livejournal

  6. #6
    BMJ:
    so can you input integers thru cin? *is confused* i never thought you could.........



    ~Inquirer
    Compilers:
    GCC on Red Hat 8.1 (Primary)
    GCC on Mac OS X 10.2.4 (Secondary)

    Others:
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  7. #7
    Banal internet user
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    sure.. you can do this:
    Code:
    int x;
    std::cin >> x;
    And if they enter an integer, it will be stored as x... if they do not enter an integer.... heh, well you'll have a problem.

  8. #8
    hehe. I didn't even look that far. But, i learned something today. thanks.

    ~Inquirer
    Compilers:
    GCC on Red Hat 8.1 (Primary)
    GCC on Mac OS X 10.2.4 (Secondary)

    Others:
    MinGW on XP

  9. #9
    Banal internet user
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    You should use atoi() when getting integer input with cin

  10. #10
    Registered User
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    Thanks you guys

    Thank you very much, I understand what i did wrong

  11. #11
    Banal internet user
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    I knew you could figure it out

  12. #12
    Registered User
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    Oct 2002
    Posts
    14

    new problem

    How do i get this code to loop infinitely until the user tells it to stop?

    # include <iostream>
    # include <cmath>
    using namespace std;

    double average, sd, s1, s2, s3, s4, deviation;

    int main()
    {
    cout << "Press enter after entering a value.\n";
    cout << endl;
    cout << "Enter score one: ";
    cin >> s1;
    cout << "\nEnter score two: ";
    cin >> s2;
    cout << "\nEnter score three: ";
    cin >> s3;
    cout << "\nEnter score four: ";
    cin >> s4;

    average =(s1+s2+s3+s4)/4;
    deviation =(((s1-average)*(s1-average))+((s2-average)*(s2-average))+((s3-average)*(s3-average))+((s4-average)*(s4-average)))/3;
    sd = sqrt(deviation);

    cout << "\nThe average of your four scores is "<<average<<".\n";
    cout << "The standard deviation of your scores is "<<sd<<".\n";

    return 0;
    }

  13. #13
    Banal internet user
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    What do you mean by loop? Do you want it to go through getting all the scores? Or do you want the use to be able to stop at any time by typing 'Q' or something?

  14. #14
    Registered User
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    what i mean is that i would like the user to be able to repeat the program. i would like the user to be able to input different scores each time. This would happen over and over again until the user wanted to stop. For instance,

    average
    mean

    "would you like to run the program again? y or n"

    then they would hit "y" as long as they wanted to use the program. when they want to quit, they would hit "n"

  15. #15
    Just a Member ammar's Avatar
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    953
    Hi,
    I would really like to know how did you input integers without using cin?
    none...

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