Thread: pass tridimentional arrays

Hi, all~

we know arrays could be passed as arguments but tridimentional arrays looks a bit different from simply arrays. That is, we could implement our function like this:

Code:

int myFunction (int arr[][4][5]);

why the first [] could be blank ?

>why the first [] could be blank ?
The function doesn't need the first dimension to determine the size of the array. Simplified, this:

void func ( int array[10] );
is equivalent to
void func ( int *array );

Notice that the one dimensional array is converted to a simple pointer, so no size information is needed. A multidimensional array however, needs size information for the latter dimensions:

void func ( int array[10][10] );
is equivalent to
void func ( int (*array)[10] );

The first dimension is still a pointer, but the second is an array reference, it needs a size.

-Prelude