Thread: what does strtok return?

if strtok() finds nothing that generally means that the 2 delim chars occupy consecutive memory locations. Read up to first delim and place in an array or something. Then strcat() what you want onto the end. Then finally strcat() again onto that the end of the original string. Always make sure your destination array is big enough to cope with the 2 strcat operations without overflowing.
Simple to do with the funcs in string.h and/or pointers.

This is what I already know :
strtok() returns a pointer to a string that includes the delimiter AND replaces the delimiter by NULL.
That means: in case there are two delimiters in a row (like ;;) strtok() should return NULL. In fact it only does so at the input-string's end!

Code:

/* strtok example */
#include <stdio.h>
#include <string.h>

int main ()
{
  char str[] ="S1;;;;0;;1;;;";
  char * pch;
  cout << "Splitting string in tokens:" << endl;
  pch = strtok (str,";");
  while (pch != NULL)
  {
    cout << pch << " ";
    pch = strtok (NULL, ";");
  }
  return 0;
}

The Output looks like this: S1 0 1
If strtok() had returned NULL when it found two ';' in a row, "0 1" would be missing.

I need to fill in 0 between each ';'.
The output has to look like: S1 0 0 0 0 0 1 0 0

@ Stoned_Coder:
Surely I can append any string at EACH token I get with strcat(). But how do I append only at the tokens with "nothing" in it? I only see that my output will look like this which is not what I want:
S10 0 0 0 00 0 10 0 0
Did I get it wrong?

Thank You.