Hi,
Could someone please tell me , that if I've a function that takes a void* as an argument, then, is there any way to know, exactly which type of pointer has been passed by the calling function.
e.g.
[code tags added by ygfperson]Code:int main() { int i=5; func(&i); char c='c'; func(&c); } void func(void* p) { // How can I know here, whether to cast p as int*, or char* to read the correct values ?? }
You can't, well not that I know of. Why don't you make 2 functions OR use templates. Look them up on google or here if you need further explanation.Originally posted by palette
Hi,
Could someone please tell me , that if I've a function that takes a void* as an argument, then, is there any way to know, exactly which type of pointer has been passed by the calling function.
e.g.
int main()
{
int i=5;
func(&i);
char c='c';
func(&c);
}
void func(void* p)
{
// How can I know here, whether to cast p as int*, or char* to read the correct values ??
}
Not easilly......that's the problem with void pointers.....they strip away type info...Originally posted by palette
Hi,
Could someone please tell me , that if I've a function that takes a void* as an argument, then, is there any way to know, exactly which type of pointer has been passed by the calling function.
There are better ways than ussing void params...
1. Use a pointer to a base class , inherit the data you want to pass from this base class, and pass a pointer to this bas class to the function....if you have used virtual functions properly, it should work
2. Overload the function for each type you wish to pass.
