Thread: Dynamic arrays

Code:

 int** map = new int*[10]; 
for(int i=0;i<10;i++){
    map[i] = new int[10];
}

Now why doesn't this work for me?
I've looked around everywhere, and im trying to create arrays of dynamic size. My sources tell me it should work, but i get a "parse error before 'for'."

Yet i'm not sure what is wrong there.

I got it to work by itself now, so i know its fine
Its something in the rest of my code thats wrong.

But all that is above this is a bunch of #defines.

I moved the code to directly under the #includes, and it still has the same problem :S

Code:

#include <string> 
#include <string.h>
#include <fstream> 
#include "allegro.h"
using namespace std;

int** map = new int*[40]; 
for(int i=0;i<40;i++)
{
    map[i] = new int[40];
}

It has a parse error there somewhere (same error still), before "for"

No it wasnt all my code. But i narrowed the error to this:

Code:

 int** ptr = new int*[10];
for(int i=0;i<10;++i){		
    ptr[i] = new int[10];	
}

int main(){	

ptr[0][1] = 12313; 
return 0;
}

Its not in the main function, but if i put it in there, it works. Is it illegal to try and create the array like this outside of a function?

Ok, well then how would i go about creating this as a global array?

Would vectors work?

:EDIT: Tell me im stupid for forgetting that pointers are 'global'