Thread: How do I "resize" an array?

Maybe this is stupid, but this is the code:

Code:

#include<iostream.h>
#include<stdio.h>
//#include"..\libs\myutil.h"
int main(){
   int ofnum;             //<---declaration
   cout << "How many number to enter: ";
   cin >> ofnum;
   double numbers[ofnum]; //<----------------------------problem
	for(int x=0;x <=ofnum-1; x++){
   	cout << "Enter number #" << (x+1) << ": "; // <---ask for number 5 times
      cin >> numbers[x];
   }
   double total = numbers[0];
   for(int x=1;x<=ofnum-1;x++){   // <---- add all together
   	total +=numbers[x];
   }
   total/=ofnum;           //<---get average
   cout << "Average is: " << total << endl; // <----display result
   getchar();
   return 0;
}

it says it can only accept constants. My teacher won't help me.

Use new on a pointer instead of an array.

Code:

#include<iostream.h>
#include<stdio.h>

int main(){
        int ofnum;
        cout << "How many number to enter: ";
        cin >> ofnum;
        double *numbers = new double[ofnum];
        for(int x=0;x <=ofnum-1; x++){
                cout << "Enter number #" << (x+1) << ": ";
                cin >> numbers[x];
        }
        double total = numbers[0];
        for(int x=1;x<=ofnum-1;x++){
                total +=numbers[x];
        }
        total/=ofnum;
        cout << "Average is: " << total << endl;
        delete [] numbers;
        getchar();
        return 0;
}