in a program i want the user to insert his name. then have each letter of his name turn into a variblae, like if his name is Eric....
variableone would equal E
variabletwo would equal R
varibalethree would equal I
vairbalefour would equal C
get it? I have searhc around. I tried to search th cboards but it went to slow. i tried like 10 times
if you read something into a char pointer, you already have done that.
x[0] = 'E';
x[1] = 'r';
x[2] = 'i';
x[3] = 'c';
> if you read something into a char pointer, you already have done that.In the above example, autotext has been initialized and filled already.Code:#include <iostream> using namespace std; int main ( void ) { char * autotext = "1 2 3 4 5 6 7 8 9 0"; char * ptrtext; for ( ptrtext = autotext; * ptrtext != '\0'; ptrtext++ ) { cout << * ptrtext << endl; } return 0; }
However, if you were to fill it later on in your program, this would still work.
autotext is an array of 20 characters.
I'm printing each one on a new line, with a carriage return inbetween each one.
You may manipulate the data as needed.
The world is waiting. I must leave you now.
Code:#include <string> #include <iostream> using namespace std; int main() { string name; int foo=0; int length; cin>>name; length=name.length()-1; while(foo<length) { cout<<name[foo]<<endl; foo++; } return 0; }
