Overloading probs

[reyal]

Anyone know how to overload a += operator in a rational problem?

Ex:

rational r1 = 5/6
rationa r2 = 3/5

r1+=r2

r1 will have a new value 43/30.

any help will be much appreciated.

[endo]

I'm not familiar with rationals, but you have to think about how they are added normally and then apply that to the overloaded operator. += is usually declared as a member function so the code might look something like this:

rational& rational::operator +=( rational& rvalue )
{
      //addition code
     return *this;
}

If you explain rationals for me (I cant be arsed to search at the moment), I'lll probably be able to help more.