using 2-d arrays

• 08-17-2002
newbie40
using 2-d arrays
hi, im creating a game that solves an 8 puzzle
i need to take in 9 numbers, 0-9 and i need it to be a 3X3 matrix because the "board" uses a 2-d array. how do i cin those numbers??

int main () {

int maxNum;

cout << "Welcome to the Eight-Puzzle Solver." << "\n"

<< "What is the upper limit on the number of"
<< " nodes I should search?" << endl;

cin >> maxNum;

cout << "\n" << "\n"
<< "Please input 9 digits (0--8) to" << "\n"
<< "specify the initial board position:";

cin >> ????

}
• 08-17-2002
doing a search of the board will provide you with a number of similar responses.

also 0 - 9 is ten numbers, not nine.

Basically you use double index operators to access each spot.

int 2D[3][3];
for(i = 0; i < 3; i++)
{
for(x = 0; x < 3; x++)
{
2D[i][x] = (3 * i) + x;
}
}
• 08-17-2002
newbie40
oops, i mean 0-8, sorry

so do i just

cin >> num1 >> num2 >> num3 >> num4 >> num5 >> num6 >> num7 >> num8 >> num9;

and then assign these numbers to a 2d array?

thanks for the help.
• 08-17-2002
Hammer
An example:
Code:

```#include <iostream> using namespace std; int main(void) {     int board[3][3] = {{0,0}};         for (int i = 0; i < 3; i++)         for (int j = 0; j < 3; j++)         {             cout <<"Enter Row " <<i <<" Col " <<j <<" :";             cin >> board[i][j];         }             for (int i = 0; i < 3; i++)         for (int j = 0; j < 3; j++)             cout <<"Row " <<i <<" Col " <<j <<" :" <<board[i][j] <<endl;         return 0;     }```
• 08-17-2002