Thread: Problem with code (newbie question)

#include <stdlib.h>
#include <iostream.h>

int main(void)
{
int i;

for (i = 0; i < 1000; i++)
{

cout<<"00101001101010110";
i++;

}
system("CLS");
return 0;
}


Well when I run this program there is still a little bit of 0101011101100.... and the screen was not totally cleared. :*(

thanks in advance

Add the line:
cout<<endl;
just before the call to system("cls")

i think the program cleared the screen before printing all of the data out. i'm not really sure on this, though.

one technical warning: you don't need another i++ at the end of the for loop. the one in the declaration should do the job fine. if you want to skip 2 each iteraton, do i+=2;

//edit: beaten...
endl flushes the output buffer, so that should do the trick

Thanks Unregistered. Ive been banging my head against the wall tyring to figure this out and the answer is so simple! hehe.

I posted reply #2 above. I think the technical answer to this is that the cout object ( a global instance of a class ) has an internal buffer that is not immediately flushed to the Windows screen buffer. Your output fills the cout buffer, & is flushed, then the remainder is written to the cout buffer, and is not flushed. Then you clear the screen. Then the program exits, causing the cout object's destructor to fire off, which flushes the remaining portion of the buffer to the screen buffer. Just a guess on all that.