Thread: Operand function??

I am new to C, C++ programming. I do have 3 years of heavy VB experience and here is my problem:

I am converting a C program to VB and I am almost done, but I do not understand what the following line of code in the original C program is doing. Here it is:

Code:

errflag->dir = 1;

The part I do not understand is the operand symbols, ->

errflag minus greater than dir = 1

Can anyone clear the fog??

Thanks for any info.

Code:

errflag->dir = 1;

The above is a shorthand for saying this

Code:

(*errflag).dir = 1;

And the '->' syntax is used in boh C and C++ for the same reason.

That's it!!!

Thank you so much for your expertise.

I did not see this code at the top of the program:

Code:

struct n_d_flags        
{
	int dir;
	int numtaps;
	int rerr;
};

Code:

errflag->dir = 1;

Is this expression saying:

If errflag then set the variable dir in the structure n_d_flags to 1?

Thanks again.

Is this expression saying:

If errflag then set the variable dir in the structure n_d_flags to 1?

It's not saying if anything!!

It's directly assigning 1 to the member variable 'dir' in the object/structure 'errflag'.

DOH!

I see. I understand 100% now.

It is simply assigning a 1 to dir in the structure n_d_flags.

Thanks so much for your help.

I have it working in my VB app now.