thanks i modified the code to:

Code:

void median( int answer[], int size )
{
cout << "\n********\n Median\n********\n"
<< "The unsorted array of responses is";
printArray( answer, size );
bubbleSort( answer, size );
cout << "\n\nThe sorted array is";
printArray( answer, size );
if ( size % 2 == 0) {
cout << "\n\nThe median elements are " << size / 2
<< " and " << ( size / 2 ) + 1 << " of\nthe sorted "
<< size
<< " element array.\nFor this run the median is "
<< (answer[ size / 2] + answer [ ( size / 2 ) + 1]) / 2
<< "\n\n";
}
else {
cout << "\n\nThe median is element " << size / 2
<< " of\nthe sorted " << size
<< " element array.\nFor this run the median is "
<< answer[ size / 2 ] << "\n\n";
}
}

I never would have thought about using mod 2 which is the heart of what i needed .

Now i have a different problem. This time im doing mode and here is my code for the function:

Code:

void mode( int freq[], int answer[], int size )
{
int rating, largest = 0, modeValue = 0;
cout << "\n********\n Mode\n********\n";
for ( rating = 1; rating <= 9; rating++ )
freq[ rating ] = 0;
for ( int j = 0; j < size; j++ )
++freq[ answer[ j ] ];
cout << "Response"<< setw( 11 ) << "Frequency"
<< setw( 19 ) << "Histogram\n\n" << setw( 55 )
<< "1 1 2 2\n" << setw( 56 )
<< "5 0 5 0 5\n\n";
for ( rating = 1; rating <= 9; rating++ ) {
cout << setw( 8 ) << rating << setw( 11 )
<< freq[ rating ] << " ";
if ( freq[ rating ] > largest ) {
largest = freq[ rating ];
modeValue = rating;
}
for ( int h = 1; h <= freq[ rating ]; h++ )
cout << '*';
cout << '\n';
}
cout << "The mode is the most frequent value.\n"
<< "For this run the mode is " << modeValue
<< " which occurred " << largest << " times." << endl;
}

what it basically does is display the types of responses, the frequency at which those responces occurred (it puts that data in a nice tabular format) and alongside a histogram of the data. It then states the mode and its frequency. Now my problem, I'm having trouble with an array of a "tie" of mode values (example: 8 and 9 both occurred 20 times) and it only displays 8 occuring 20 times. How can i fix it so it will display both items or more than two for that matter if there is a more-than-two way tie?