Thread: need example of toupper()

Here's how im using toupper();
cin>>whatever;
whatever.toupper();
debug says it requires a struct/union type...so i'm guessing i can't do it that way...
first i tried this:
cin>>whatever;
whatever=toupper(whatever);
then it complains about whatever not being an integer...
can someone give me a working example of toupper to work from? thanks.

I am assuming whatever is a char type variable. To convert the character to upper case without causing any complications use type casting...

#include<ctype.h>
#include<iostream.h>
#include<conio.h>
int main()
{
char whatever;
cin>>whatever;
whatever=char(toupper(whatever));
cout<<endl<<whatever;
cout<<endl<<"Press any key to close this window...";
getch();
return 0;
}

Compiler:Borland C++ 5.0

heres what i did, essentially:

Code:

cin>>whatever;
int whatever2=reinterpret_cast <int> (whatever);
whatever2=toupper(partNumber2);
//that works...

but, i'm going to look for whatever2 inside another string: strstr();
i couldn't just use whatever2 because now it's an integer variable...i need to get it back to a char[], and use it inside strster();, i tried a couple of casting methods, but none of them will work according to the compiler...what can i do?

char cMyChar = 'a';
cMyChar = toupper((int)cMyChar);

Are you sure that won't work? It works fine for me, and has in the past on a variety of compilers... What compiler are you using?

If all else fails... you could write your own toupper..

Code:

int ToUpper(int iArg)
{
     if (iArg < 123 && iArg > 96)
     {
          iArg -= 32;
     }
     return iArg;
}

ok....im mad...my code just compiles and gets fatal errors when i run it...

Code:

char whatever;//is the problem here?
cin>>whatever;//a string, possibly more than one letter, that's why I was suspicious of char whatever.
whatever=toupper((int)whatever);
//I read a string from a file into char *b
strstr(b,(const char*)partNumber);
//then i do some stuff like if the above returns null the string was not found...etc.

whats going on?

I use MS Visual C++ 6 Professional

Hi. When you say char whatever, you are declaring a char type variable. however the prototype of the toupper function is...
int toupper(int);
i.e. it returns an int value.

If you want to assign the int value to a char variable, you must convert this int value to char, using type casting...
whatever=char(toupper(whatever));

This would do the same thing as...
whatever=char(toupper(int(whatever)));
The conversion of whatever to int takes place automatically.

Also, when u say cin>>whatever, you are not taking an entire string as input, you are taking only one single character as input. In order to input a string you should declare a char array, and use gets. To convert it to upper case use strupr.

#include<iostream.h>
#include<conio.h>
#include<stdio.h> //for gets
#include<string.h> //for strupr
int main()
{
char whatever[50];
cout<<"Enter string:"; gets(whatever);
cout<<"The string in upper case is:"<<strupr(whatever);
cout<<endl<<"Press any key to close this window...";
getch();
return 0;
}

The toupper function works on characters only, and not strings.

Compiler:Borland C++ 5.0

"Do you want to fish the lower river?"
"No, I want to go toupper river."