Thread: String Statement problem

ok i declared string word2; in c++ borland vrs 6 and i wanted to add records or varibles , whatever you call them so i wrote it like this string word2[10]; now it runs the program but what i want to be displayed does not display the amount of characters i am reading is no more then 5 so 10 should work fine. i need to know why its not displaying heres a peice of code that might help you solve my problem.

#include <string.h>

string word2[10];

for(a = 1;a <= filecount; a = a + 1)//filecount counts how many
times it loops in scan.
{
cout << word2[a] <<" ";
}

now this should display word2 but it doesn't plz help

The code you have posted does not have anything in word2. And you do not need to loop to display the array:

const int WORD_SIZE = 10;

char word[WORD_SIZE];

strcpy( word, "Hello" ); // Put something in the array

cout << word << endl; // you can output it like a char pointer

Thanks for the help i thought i had to use a string to compare to the characters in the .txt file i was scanning thanks for the help!

I have a quick little question. I notice that most of the time I see people asking about string.h, but why not just use APstring?(and the other APclasses for that matter ie..apvector, apmatrix) Is it just you reply using what the original post-er used. Or is it that you dont use it much. Im just curious to know how many actually use these...thanks

I'm not sure what you're trying to do here.... string word2[10]; creates an array of 10 strings. You only need string word2; or char word2[10];.

Also, if you wanted to use that loop to display it, a should start at 0 (array elements are numbered starting at 0)